During the isothermal heat addition process of a Carnot Cycle, 900 kJ of heat is added to the working fluid from a source at 400oC. Determine:
a.) the entropy change of the working fluid
b.) the entropy change of the heat source
c.) the total entropy change of the universe for this process.
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3 comments:
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HINTS:
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* If the system is isothermal and reversible, then change in entropy can be evaluated from the definition of entropy.
* Be careful with the sign for each Q.
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ANSWERS:
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deltaS = 1.34 kJ/K (fluid)
How is the change in entropy found for the heat source? I can not find an equation in the book for dSresv.
Dear Anonymous,
Whether you are looking at the surroundings (reservoir) or the system (fluid), the equation is the same: entropy change = entropy transfer plus entropy generation, or deltaS = integral(dQ/T) + Sgen.
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