A Carnot refrigerator operates in a room in which the temperature is 25°C. The refrigerator consumes 500 W of power when operating and has a COP of 4.5. Determine ...
a.) The rate of heat removal from the refrigerated space
b.) The temperature of the refrigerated space
4 comments:
Ok, so I'm having a bit of trouble with part a of this problem. I first got Tc, and that was correct, and I used that (Tc/Th)=(Qc/Qh) and W = Qh-Qc to solve for Qc. I got about 200 watts which if watts= kJ/s gives me about 37 kJ/min. Then I decided to do the definition of CoP for refrigerators: Cop=(Qc/W) and i get 2250 W or 37.5 kJ/min. Am I wrong in thinking the power into the system is the W?
DKress 1:01 AM
One problem is that 1 Watt = 1 J/s, not 1 kJ/s. I think this is the only problem with what you are doing.
where can i see the answer and the solution to this problem?
DKRESS solved the problem near the end.
Qc = 2250W
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