Learning undergraduate engineering thermodynamics might be less painful with a blog. I hope that students, faculty and interested observers will share their thoughts on the laws of thermodynamics, phase and chemical equilibrium and many related topics.
Again asking the same question that "questionguy" did, wasn't this problem got cut out of the hw as told by the professor in an e-mail that he sent to the whole class last Thursday.
Bill Clinton: The key is P* = Psat and you can lookup Psat data in the ammonia tables in the appendix of your book. For clapeyron, estimate dP*/dT as deltaP* / deltaT. For Clausius-Clapeyron, determine the slope as delta[Ln{P*}]/delta[1/T]. In both cases, use the slope to determine the latent heat of vaporization.
QuestionGuy: Do the units one at a time using the unit conversions in the back of your book. You will also need the molecular weight to get from mass to moles or vice-versa. 1 J = 9.478e-4 Btu 1 gmole = 17 g/gmole 1 lbm = 453.593 g
13 comments:
is the posted answer to this question (part a) correct?
nm, i got it
is this question be cancelled by Dr. B?
Delta V wiggle vaporization is just the two V values listed in the thermo table, the vapor minus the liquid value, changed into m^3 per mole?
i was zoning out in class when we talked about solving this one (a and b)....can anyone offer some help?? thank you
does anybody know how to change the unit from (J/mol) to (Btu/lbm)?
Again asking the same question that "questionguy" did, wasn't this problem got cut out of the hw as told by the professor in an e-mail that he sent to the whole class last Thursday.
QuestionGuy:
No, this problem has not been cancelled.
Questioning:
Yes.
Bill Clinton:
The key is P* = Psat and you can lookup Psat data in the ammonia tables in the appendix of your book.
For clapeyron, estimate dP*/dT as deltaP* / deltaT. For Clausius-Clapeyron, determine the slope as delta[Ln{P*}]/delta[1/T].
In both cases, use the slope to determine the latent heat of vaporization.
QuestionGuy:
Do the units one at a time using the unit conversions in the back of your book. You will also need the molecular weight to get from mass to moles or vice-versa.
1 J = 9.478e-4 Btu
1 gmole = 17 g/gmole
1 lbm = 453.593 g
Anonymous:
No, this problem was not cut out. You must have printed the HW AFTER I updated the assignment page.
JustWondering:
Yes, I think my answer is correct. Why do you ask ?
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