Saturday, April 01, 2006

HW #2 - P #6 - An Application of Equations of State

A 0.016773 m3 tank contains 1 kg of R-134a at 110oC. Determine the pressure of the refrigerant using:
a.) the ideal gas EOS
b.) the generalized compressibility chart
c.) the refrigerant tables
d.) van der Waals EOS
e.) Soave-Redlich-Kwong EOS

8 comments:

Anonymous said...

I am trying to read the compressibility chart given in class. Are the dashed lines the ideal reduced molar volume or something else? I can tell the Tr line and I assume our Z and Pr values are where the two lines meet. How accurate do we need to be? (I got 0.4 for a Pr value and that set off my answer pretty far...) Thank you for your time!

Anonymous said...

Never mind, I got it (the difference surprised me, then I realized it's supposed to be!) Thanks anyway!

Dr. B said...

Lisa 3:54 & 4:05 AM
Wow, doing thermo at 4 AM ? Sleep !
Yes, the dashed lines are lines of constant ideal reduced molar volume.

Correct again. To summarize for other readers...
Pr = 0.4 is not so bad. Yes, this gives an answer MUCH different than the IG EOS. But it is the IG EOS that is not accurate ! That is really the whole point of using better EOS's such as the compressibility charts.

Good work, especially for 4 AM !

Anonymous said...

I must have missed something in class but what are the refrigerant tables?

Dr. B said...

Anon @ 6:58
R-134a is a refrigerant. In this case, the refrigerant tables are the R-134a tables.

Anonymous said...

On part d) of this problem, I'm getting an answer that is about 370 kPa higher than the answer given on the homework. I've double- and triple-checked my calculations and units as well as the correctness of the Van der Waal's equation P = (RT/V-b) - a/V^2 (V being V wiggle that worked for all other parts). Is there some common mistake here that I could be overlooking?

Dr. B said...

Carina 10:22 PM
The most common mistakes when using the more sophisticated EOS eqns involve units. I suggest ou stick with P [=] Pa, V~ [=] m^3/mole and T [=] Kelvin. Can you tell me what values you got for a & b ? Maybe your values for T & V~ and their units would help too.

Dr. B said...

Carina 10:22 PM
The other possibility is R. With the units I mentioned in my last comment, you should use R = 8.314 J/mol-K = 8.314 Pa-m^3/mol-K.