<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:georss='http://www.georss.org/georss' xmlns:gd='http://schemas.google.com/g/2005' xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-20953269</id><updated>2012-01-23T13:33:04.448-08:00</updated><title type='text'>Thermodynamics</title><subtitle type='html'>Learning undergraduate engineering thermodynamics might be less painful with a blog.  I hope that students, faculty and interested observers will share their thoughts on the laws of thermodynamics, phase and chemical equilibrium and many related topics.</subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default?max-results=100'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><link rel='next' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default?start-index=101&amp;max-results=100'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>286</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>100</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-20953269.post-8811200365335114529</id><published>2011-06-06T15:05:00.000-07:00</published><updated>2011-06-06T15:05:31.845-07:00</updated><title type='text'>ENGR 224 - Final Exam , June 13, 2011, 9-11AM, SMT 354</title><content type='html'>Please post any questions relating to the final exam as comments on this blog post.&lt;br /&gt;&lt;br /&gt;The comprehensive final covers CB chapters 1 - 7 and the assigned parts of chapters 9 - 11 or LT chapters 1 - 10.&lt;br /&gt;&lt;br /&gt;The test will be a 2-hour, closed book test.  You will be allowed to use FOUR 8.5"x11" cheat sheets.  You can write or print on both sides of your cheat sheets.&lt;br /&gt;&lt;br /&gt;It has been a great pleasure to work with you this quarter.  I know it is a challenging course, but you cam through in good form.  Best of luck to you in your career ahead.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-8811200365335114529?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/' title='ENGR 224 - Final Exam , June 13, 2011, 9-11AM, SMT 354'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/8811200365335114529/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=8811200365335114529' title='14 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8811200365335114529'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8811200365335114529'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/06/engr-224-final-exam-june-13-2011-9-11am.html' title='ENGR 224 - Final Exam , June 13, 2011, 9-11AM, SMT 354'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>14</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-7281097790371023689</id><published>2011-05-24T16:19:00.000-07:00</published><updated>2011-05-24T16:19:52.274-07:00</updated><title type='text'>ENGR 224 - HW #7</title><content type='html'>This HW covers CB chapters 9-11 or LT chapters 9 &amp; 10.&lt;br /&gt;&lt;br /&gt;The homework consists of 7 problems for a total of 48 pts.&lt;br /&gt;&lt;br /&gt;Please begin your question with the problem number you are asking about.&lt;br /&gt;&lt;br /&gt;9.116 - Brayton Cycle with Regeneration - 8 pts&lt;br /&gt;11.76 - Helium Gas Refrigeration Cycle - 6 pts&lt;br /&gt;WB-1 : Brayton Cycle with Variable Heat Capacities - 6 pts&lt;br /&gt;WB-2 : Effect of Turbine Feed T on Rankine Cycle Efficiency  - 6 pts&lt;br /&gt;Wb-3 : Special Rankine Cycle with Reheat and Regeneration - 8 pts&lt;br /&gt;Wb-4 : Ammonia Cascade Refrigeration Cycle - 8 pts&lt;br /&gt;WB-5 : Vapor-Compression Heat Pump - 6 pts&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-7281097790371023689?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/Homework/hw7.htm' title='ENGR 224 - HW #7'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/7281097790371023689/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=7281097790371023689' title='41 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7281097790371023689'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7281097790371023689'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/05/engr-224-hw-7.html' title='ENGR 224 - HW #7'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>41</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-1106959307347923247</id><published>2011-05-20T15:25:00.000-07:00</published><updated>2011-05-20T15:25:51.513-07:00</updated><title type='text'>ENGR 224 - Test #2 , May 24, 2011</title><content type='html'>Please post any questions relating to the second test as comments on this blog post.&lt;br /&gt;&lt;br /&gt;Test 2 will focus on CB chapters 6 &amp; 7 or LT chapters 6 - 8.  Material from earlier chapters will also be part of this test, although it will not be the focus.&lt;br /&gt;&lt;br /&gt;The test will be available for you to take between 8AM and 7PM in the Testing Center on Tuesday, 5/24/11.  It is a 2-hour, closed book test.  You will be allowed to use TWO 8.5"x11" cheat sheets.  You can write or print on both sides of your cheat sheets.  You will be penalized ONE point for every TWO minutes over 2 hours that you have the test in your possession.  Do NOT forget the time stamps !&lt;br /&gt;&lt;br /&gt;We will have an optional test-prep class on Mon, 5/23, and NO CLASS MEETING on Tue, 5/24.  There is a QUIZ on 5/25.  It is not my fault.  The testing center situation messed up our schedule.&lt;br /&gt;&lt;br /&gt;Best of luck to you !&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-1106959307347923247?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/' title='ENGR 224 - Test #2 , May 24, 2011'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/1106959307347923247/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=1106959307347923247' title='42 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1106959307347923247'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1106959307347923247'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/05/engr-224-test-2-may-24-2011.html' title='ENGR 224 - Test #2 , May 24, 2011'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>42</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-8292150136281009026</id><published>2011-05-16T10:21:00.000-07:00</published><updated>2011-05-16T10:21:08.644-07:00</updated><title type='text'>ENGR 224 - HW #6</title><content type='html'>This HW covers CB chapter 7 or LT chapter 8.&lt;br /&gt;&lt;br /&gt;The homework consists of 15 problems for a total of 71 pts.&lt;br /&gt;&lt;br /&gt;Please begin your question with the problem number you are asking about.&lt;br /&gt;&lt;br /&gt;Cengel &amp; Boles: Ch 7:&lt;br /&gt;&lt;br /&gt;7.127 - Power Requirement for an Air Compressor - 5 pts&lt;br /&gt;7.131 - Analysis of an R-134a Compressor - 6 pts&lt;br /&gt;7.146+ - Lost Work in a Heat Exchanger - 6 pts&lt;br /&gt;Additional part c.) Determine the rate at which work is lost due to the irreversible nature of heat transfer in this process in kW. Assume the surroundings are at 20oC.&lt;br /&gt;&lt;br /&gt;WB-1 -  Back-Work Ratio of a Steam Power Cycle  - 7 pts&lt;br /&gt;Problem Statement :  &lt;br /&gt;Consider a steam power plant that operates between the pressure limits of 8 MPa and 20 kPa. Steam enters the pump as a saturated liquid and leaves the turbine as a saturated vapor. Determine the back work ratio (BWR is the ratio of the work delivered by the turbine to the work consumed by the pump). Assume the entire cycle to be reversible and the heat losses from the pump and the turbine to be negligible.&lt;br /&gt;&lt;br /&gt;Hints :  &lt;br /&gt;Assume the cycle operates at steady-state and that the ump and turbine are reversible.&lt;br /&gt;I suggest you make a table with 6 columns. The 1st column lists all the important properties you may need to evaluate for each steam in the cycle. Make a column for each of the 4 streams in the cycle. The last column should list the units for each variable. This table should help you keep track of what you know and what you still need to determine.&lt;br /&gt;&lt;br /&gt;Make a nice process flow diagram. Make a nice TS Diagram. Include the 2-phase envelope and the two key isobars. Apply the 1st and 2nd Laws to the pump and turbine and you should be able to determine the BWR.&lt;br /&gt;&lt;br /&gt;Two double-interpolations are required unless you use NIST or a plug-in for Excel or your calculator.&lt;br /&gt;&lt;br /&gt;Ans.: BWR ~ 240&lt;br /&gt;&lt;br /&gt;WB-2 -  Polytropic Compression of N2 with Varying δ - 6 pts&lt;br /&gt;Problem Statement :  Nitrogen gas is compressed from 80 kPa and 27oC to 480 kPa by a 10 kW compressor. Determine the mass flow rate of nitrogen through the compressor assuming the compression process is …&lt;br /&gt;a.) Isentropic, γ = 1.4&lt;br /&gt;b.) Polytropic with δ = 1.3&lt;br /&gt;c.) Isothermal&lt;br /&gt;d.) Ideal, two-stage polytropic with δ = 1.3&lt;br /&gt;&lt;br /&gt;Hints :  &lt;br /&gt;The compressor operates at steady-state.    &lt;br /&gt;Changes in kinetic and potential energies are negligible.   &lt;br /&gt;Flow work and shaft work are the only forms of work that cross the system boundary.&lt;br /&gt;Nitrogen (N2) behaves as an ideal gas in all parts of this problem.   &lt;br /&gt;The heat capacities of N2 are constant and, therefore, γ is also constant.&lt;br /&gt;The intercooler in part (d) cools the effluent from the first compressor back down to T1 before it enters the second compressor.&lt;br /&gt;&lt;br /&gt;Parts (b), (c) and (d) should be plug-and-chug.&lt;br /&gt;&lt;br /&gt;Ans.: a.) Mdot ~ 0.048 kg/s , c.) Mdot ~ 0.063 kg/s&lt;br /&gt;&lt;br /&gt;WB-3 -  Entropy Change, Heat Transfer and Irreversibilities - 7 pts&lt;br /&gt;Problem Statement :  &lt;br /&gt;A closed system undergoes a process in which work is done on the system and heat transfer Q occurs only at temperature Tb. For each case listed below, determine whether the entropy change of the system is positive, negative, zero or indeterminate (you cannot tell for sure from the given information).&lt;br /&gt;a.) Internally reversible process with Q &gt; 0.&lt;br /&gt;b.) Internally reversible process with Q = 0.&lt;br /&gt;c.) Internally reversible process with Q &lt; 0.d.) Internal irreversibilities present with Q &gt; 0.&lt;br /&gt;e.) Internal irreversibilities present with Q = 0.&lt;br /&gt;f.) Internal irreversibilities present with Q &lt; 0.Hints :Consider the sign of each term in the defining equation for entropy generation.&lt;br&gt;&lt;br&gt;&lt;br /&gt;WB-4 -  Entropy Generation and Lost Work in a Nozzle - 6 pts&lt;br /&gt;Problem Statement :  &lt;br /&gt;Oxygen, O2, enters a nozzle operating at steady-state at 3.8 MPa, 387oC and 10 m/s. At the nozzle exit, the conditions are 150 kPa, 37oC and 790 m/s.&lt;br /&gt;a.) For a system that encloses the nozzle only, determine the heat transfer (kJ/kg) and the change in specific entropy (kJ/kg-K), both per kg of oxygen flowing through the nozzle. What additional information would be required to evaluate the rate of entropy production in this process ?&lt;br /&gt;b.) Using an enlarged system boundary that includes the nozzle and a portion of its immediate surroundings, evaluate the rate of entropy generation (kJ/kg-K) and the rate of lost work (kJ/kg), both per kg of oxygen flowing through the nozzle. Assume that heat exchange at the enlarged system boundary takes place at the ambient temperature, 20oC.&lt;br /&gt;&lt;br /&gt;Treat O2 as an ideal gas with variable heat capacities. Verify that the ideal gas assumption is valid.&lt;br /&gt;&lt;br /&gt;Hints :&lt;br /&gt;In part (a), use the 1st Law and the ideal gas property tables to determine Q.&lt;br /&gt;In part (b), evaluate the entropy generation from its definition, using the Ideal Gas Property Tables and Gibbs 2nd Equation.&lt;br /&gt;Lost work is just the product of Tsurr and Sgen.&lt;br /&gt;&lt;br /&gt;Ans.: a.) Q ~ -30 kJ/kg , b.) Sgen ~ 0.2 kJ/kg-K and Wlost ~ 61 kJ/kg&lt;br /&gt;&lt;br /&gt;WB-5 -  Lost Work in an Air Compressor and HEX - 7 pts&lt;br /&gt;&lt;br /&gt;Problem Statement :&lt;br /&gt;Air flows through the compressor and heat exchanger in the system shown in the diagram. A separate liquid water stream (CP,W = 4.18 kJ/kg-K) also flows through the heat exchanger. The data given on the diagram are based on steady-state operation. Consider the air to be an ideal gas and neglect heat exchange with the surroundings as well as changes in kinetic and potential energies. Determine...&lt;br /&gt;a.) The compressor power requirement in kW and the mass flow rate of the cooling water in kg/s.&lt;br /&gt;b.) The rate of entropy generation in kW/K and the rate at which work is lost in kW for the compressor. Assume the temperature of the surroundings is 300 K.&lt;br /&gt;c.) The rate of entropy generation in kW/K and the rate at which work is lost in kW for the heat exchanger. Assume the temperature of the surroundings is 300 K.&lt;br /&gt;&lt;br /&gt;&lt;div class="separator" style="clear: both; text-align: center;"&gt;&lt;a href="http://3.bp.blogspot.com/-rqkhngjIm3k/TdFcqC3LpPI/AAAAAAAAATQ/Y_BMdR_Ddfc/s1600/hw6-sp11-WB5.png" imageanchor="1" style="margin-left:1em; margin-right:1em"&gt;&lt;img border="0" height="240" width="320" src="http://3.bp.blogspot.com/-rqkhngjIm3k/TdFcqC3LpPI/AAAAAAAAATQ/Y_BMdR_Ddfc/s320/hw6-sp11-WB5.png" /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;Hints :  &lt;br /&gt;Use the ideal gas EOS and the volumetric flow rate to determine the mass flow rate.&lt;br /&gt;Use an energy balance to determine the work for the compressor in kW.&lt;br /&gt;To determine the water flow rate, draw the control volume enclosing the heat exchanger. This control volume has 4 mass flows entering or leaving but no Q or W. An energy balance on this control volume yields the water flow rate.&lt;br /&gt;Very important point- the air and the water DO NOT MIX in the heat exchanger !&lt;br /&gt;Determine the change in enthalpy of the water using: ΔH = Cp ΔT and determine the entropy change of the water using ΔS = CP Ln[T2/T1].&lt;br /&gt;        &lt;br /&gt;Part (b) Don't forget about the cooling water when you calaculate the entropy generated.&lt;br /&gt;&lt;br /&gt;Ans.: a.) WS ~ -50 kW, b.) Sgen,comp ~ 0.020 kW/K , Wlost,comp ~ 6 kW , b.) Sgen,HEX ~ 0.015 kW/K&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-8292150136281009026?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/Homework/hw6.htm' title='ENGR 224 - HW #6'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/8292150136281009026/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=8292150136281009026' title='30 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8292150136281009026'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8292150136281009026'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/05/engr-224-hw-6.html' title='ENGR 224 - HW #6'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/-rqkhngjIm3k/TdFcqC3LpPI/AAAAAAAAATQ/Y_BMdR_Ddfc/s72-c/hw6-sp11-WB5.png' height='72' width='72'/><thr:total>30</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-8793289317703674011</id><published>2011-05-04T17:37:00.000-07:00</published><updated>2011-05-04T17:37:00.880-07:00</updated><title type='text'>ENGR 224 - HW #5</title><content type='html'>This HW covers CB chapter 7 or LT chapter 7.&lt;br /&gt;&lt;br /&gt;The homework consists of 13 problems for a total of 59 pts.&lt;br /&gt;&lt;br /&gt;Please begin your question with the problem number you are asking about.&lt;br /&gt;&lt;br /&gt;Cengel &amp; Boles: Ch 7: 14(2pts), 15(2pts), 18(2pts), 28E(4pts), 29(6pts), 66(6pts)&lt;br /&gt;&lt;br /&gt;WB-1(4pts) , WB-2(6pts), WB-3(4pts) , WB-4(4pts), WB-5(8pts) , WB-6(5pts), WB-1(6pts)&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-8793289317703674011?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/ENGR224/Homework/hw5.htm' title='ENGR 224 - HW #5'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/8793289317703674011/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=8793289317703674011' title='39 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8793289317703674011'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8793289317703674011'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/05/engr-224-hw-5.html' title='ENGR 224 - HW #5'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>39</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-5129552757211560108</id><published>2011-04-23T09:59:00.000-07:00</published><updated>2011-04-23T09:59:23.766-07:00</updated><title type='text'>ENGR 224 - Test 1</title><content type='html'>Monday, 4/25/11 at 9AM in SMT 354.&lt;br /&gt;&lt;br /&gt;Please post any questions you have relating to the 1st test as comments on this blog entry.&lt;br /&gt;&lt;br /&gt;Test 1 covers Ch 1-5 in Cengel &amp; Boles and in LearnThermo.com.&lt;br /&gt;&lt;br /&gt;Best of luck !&lt;br /&gt;Dr. B&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-5129552757211560108?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/ENGR224/' title='ENGR 224 - Test 1'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/5129552757211560108/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=5129552757211560108' title='27 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5129552757211560108'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5129552757211560108'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/04/engr-224-test-1.html' title='ENGR 224 - Test 1'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>27</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-4875776929549060861</id><published>2011-04-20T17:59:00.000-07:00</published><updated>2011-04-20T17:59:26.557-07:00</updated><title type='text'>ENGR 224 - HW #4</title><content type='html'>This HW covers CB chapter 6 or LT chapter 6.&lt;br /&gt;&lt;br /&gt;The homework consists of 8 problems for a total of 45 pts.&lt;br /&gt;&lt;br /&gt;Please begin your question with the problem number you are asking about.&lt;br /&gt;&lt;br /&gt;Cengel &amp; Boles: Ch 6:&lt;br /&gt;6.79 - Effect of Source and Sink Temperatures on HE Efficiency - 6 pts&lt;br /&gt;6.85 - Thermal Efficiency of a Geothermal Power Plant - 3 pts&lt;br /&gt;6.107 - Carnot HE Used to Drive a Carnot Refrigerator - 6 pts&lt;br /&gt;6.110 - Actual and Maximum COP of an Air-Conditioner - 8 pts&lt;br /&gt;6.134 - Thermal Efficiency of Heat Engines in Series - 4 pts&lt;br /&gt;&lt;br /&gt;Special Problems&lt;br /&gt;WB-1 - "Show That" Problem Using the K-P Statement of the 2nd Law - 6 pts&lt;br /&gt;WB-2 - Reversible, Irreversible and Impossible Power Cycles - 6 pts&lt;br /&gt;WB-3 - A Reversible HE Used to Drive a Reversible Heat Pump - 6 pts&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-4875776929549060861?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/ENGR224/Homework/hw4.htm' title='ENGR 224 - HW #4'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/4875776929549060861/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=4875776929549060861' title='18 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4875776929549060861'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4875776929549060861'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/04/engr-224-hw-4.html' title='ENGR 224 - HW #4'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>18</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-6337796885081960127</id><published>2011-04-13T17:33:00.000-07:00</published><updated>2011-04-19T09:23:41.193-07:00</updated><title type='text'>ENGR 224 - HW #3</title><content type='html'>This HW covers CB chapter 5 or LT chapter 5.&lt;br /&gt;&lt;br /&gt;The homework consists of 10 problems for a total of 65 pts.&lt;br /&gt;&lt;br /&gt;Please begin your question with the problem number you are asking about.&lt;br /&gt;&lt;br /&gt;Cengel &amp; Boles, Ch 5: &lt;br /&gt;5.35 - Adiabatic Steam Nozzle - 5 pts&lt;br /&gt;5.54 - Adiabatic Gas Turbine - 5 pts&lt;br /&gt;5.112 - Steam Flow in a HEX Tube - 5 pts &lt;br /&gt;5.138 - Filling a Balloon with Helium - 10 pts&lt;br /&gt;5.142 - Charging a Cylinder with a Spring-Loaded Piston - 8 pts&lt;br /&gt;&lt;br /&gt;Special Problems&lt;br /&gt;WB-1 - Effluent Pressure in a Non-Adiabatic Steam Diffuser - 5 pts&lt;br /&gt;WB-2 - Steady-State, Polytropic Air Compressor - 5 pts &lt;br /&gt;WB-3 - Analysis of a Two-Stage, Adiabatic Turbine - 6 pts&lt;br /&gt;WB-4 - Analysis of an Adiabatic Steam De-Superheater - 8 pts &lt;br /&gt;WB-5 - Waste Heat Steam Generator - 8 pts&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-6337796885081960127?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/ENGR224/Homework/hw3.htm' title='ENGR 224 - HW #3'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/6337796885081960127/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=6337796885081960127' title='52 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/6337796885081960127'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/6337796885081960127'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/04/engr-224-hw-3.html' title='ENGR 224 - HW #3'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>52</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-8113237385669989230</id><published>2011-04-06T14:28:00.000-07:00</published><updated>2011-04-12T16:24:53.232-07:00</updated><title type='text'>ENGR 224 - HW #2</title><content type='html'>This HW covers CB chapters 2, 4 and parts of 6 or LT chapters 3 &amp; 4.&lt;br /&gt;&lt;br /&gt;The homework consists of 16 problems for a total of 57 pts.&lt;br /&gt;&lt;br /&gt;Please begin your question with the problem number you are asking about.&lt;br /&gt;&lt;br /&gt;Cengel &amp; Boles: Ch 3:&lt;br /&gt;&lt;br /&gt;3.26(2pts) - &lt;br /&gt;Use either the NIST Webbook or the Thermal/Fluids Toolbox (TFT) Excel plug-in.&lt;br /&gt;Use the default reference state for both the NIST and TFT.&lt;br /&gt;&lt;br /&gt;3.29E(2pts) - &lt;br /&gt;Use either the NIST Webbook or the Thermal/Fluids Toolbox (TFT) Excel plug-in.&lt;br /&gt;Use the default reference state for both the NIST and TFT. &lt;br /&gt;&lt;br /&gt;Cengel &amp; Boles: Ch 4:&lt;br /&gt;&lt;br /&gt;4.8(6pts) : W ~ -22 kJ&lt;br /&gt;4.42(5pts) : Q ~ 12750 kJ&lt;br /&gt;4.59E(4pts) : See textbook&lt;br /&gt;4.60(4pts) : ΔU ~ 6200 Btu/lbm&lt;br /&gt;&lt;br /&gt;Special Problems&lt;br /&gt;&lt;br /&gt;WB-1(5pts) : ΔHvap ~ 575 to 600 Btu/lbm&lt;br /&gt;WB-2(8pts) : ΔH14 ~ 9900 J&lt;br /&gt;WB-3(6pts): Q23 ~ -85 Btu , Wcycle ~ -20 Btu&lt;br /&gt;WB-4(3pts) : q ~ -97 Btu/h-ft2&lt;br /&gt;WB-5(3pts) : Q ~ 3500 W&lt;br /&gt;WB-6(3pts) : Lins ~ 6 cm&lt;br /&gt;WB-7(3pts) : Wb ~ 350 kJ&lt;br /&gt;&lt;br /&gt;Cengel &amp; Boles: Ch 6: 6.23(2pts), 6.41(2pts), 6.55(2pts). These problems should be pretty easy.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-8113237385669989230?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/ENGR224/Homework/hw2.htm' title='ENGR 224 - HW #2'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/8113237385669989230/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=8113237385669989230' title='56 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8113237385669989230'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8113237385669989230'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/04/engr-224-hw-2.html' title='ENGR 224 - HW #2'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>56</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-5922995758607947242</id><published>2011-03-25T10:24:00.000-07:00</published><updated>2011-03-25T10:24:15.746-07:00</updated><title type='text'>ENGR 224 - Thermodynamics at GRCC</title><content type='html'>Welcome to the Thermodynamics course at Green River Community College in Auburn, WA, USA.&lt;br /&gt;&lt;br /&gt;Feel free to post any general questions about the course as comments on this blog entry.&lt;br /&gt;&lt;br /&gt;I have created a blog entry for each chapter we will cover in this course.  If you think your question applies to a specific chapter, then please post your question as a comment on the appropriate blog entry.&lt;br /&gt;&lt;br /&gt;I have created a blog entry for each of the 7 HW assignments in the course.  If you have a question about a problem in the HW, please post it as a comment on the appropriate blog entry.  Be sure to state which problem number your question refers to !&lt;br /&gt;&lt;br /&gt;You can post your questions using your Google ID or a crazy fake name or your real name or you can post anonymously.  Whatever makes you happy.  Just don't hesitate to ASK !&lt;br /&gt;&lt;br /&gt;Remember...&lt;br /&gt;"It's not a miracle, mother, it's thermodynamics !"&lt;br /&gt;- Harrison Ford in Mosquito Coast&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-5922995758607947242?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/ENGR224/' title='ENGR 224 - Thermodynamics at GRCC'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/5922995758607947242/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=5922995758607947242' title='2 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5922995758607947242'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5922995758607947242'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/engr-224-thermodynamics-at-grcc.html' title='ENGR 224 - Thermodynamics at GRCC'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-9203069396924972368</id><published>2011-03-25T10:20:00.000-07:00</published><updated>2011-03-25T10:20:52.155-07:00</updated><title type='text'>ENGR 224 - HW #1</title><content type='html'>This HW covers CB chapters 1 &amp;amp; 3 or LT chapters 1 &amp;amp; 2.&lt;br /&gt;&lt;br /&gt;The homework consists of 15 problems for a total of 71 pts.&lt;br /&gt;&lt;br /&gt;Please begin your question with the problem number you are asking about.&lt;br /&gt;&lt;br /&gt;Cengel &amp;amp; Boles: Ch 1: 7E(3pts), 11E(4pts), 37E(2pts), 41E(3pts), 78(6pts) &lt;br /&gt;&lt;br /&gt;WB-1 (4pts) , WB-2 (5pts)&lt;br /&gt;&lt;br /&gt;Cengel &amp;amp; Boles: Ch 3: 26(4pts), 29E(4pts), 37E(5pts), 53(6pts), 66(4pts),&lt;br /&gt;83(6pts) - Assume that the air in the tire behaves as an ideal gas, but then check the validity of this assumption.&lt;br /&gt;&lt;br /&gt;WB-3 (10pts) , WB-4 (5pts)&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-9203069396924972368?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/ENGR224/Homework/hw1.htm' title='ENGR 224 - HW #1'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/9203069396924972368/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=9203069396924972368' title='21 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/9203069396924972368'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/9203069396924972368'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/engr-224-hw-1.html' title='ENGR 224 - HW #1'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>21</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-898846795680885991</id><published>2011-03-18T13:21:00.000-07:00</published><updated>2011-03-18T13:21:26.168-07:00</updated><title type='text'>HW 7B-16 - Isentropic Compression of High Quality Steam - 5 pts</title><content type='html'>Steam is compressed isentropically to a final pressure of 5 MPa.  The steam is initially at 25oC and has a quality of 91%. How much work does this process require, in kJ/kg, if the process takes place in... (a) A closed system?  (b) An open system ?  (c) Explain why the answers to parts (a) and (b) are not the same.&lt;br /&gt;&lt;br /&gt;For hints and answers visit:&lt;br /&gt;&lt;a href="http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B16"&gt;http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B16&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-898846795680885991?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B16' title='HW 7B-16 - Isentropic Compression of High Quality Steam - 5 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/898846795680885991/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=898846795680885991' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/898846795680885991'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/898846795680885991'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/hw-7b-16-isentropic-compression-of-high.html' title='HW 7B-16 - Isentropic Compression of High Quality Steam - 5 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-2076902973239217364</id><published>2011-03-16T16:21:00.001-07:00</published><updated>2011-03-16T16:21:21.119-07:00</updated><title type='text'>HW 7B-15 - Heat and Work in an Isothermal Expansion of Steam - 5 pts</title><content type='html'>Saturated water vapor is contained in a piston-and-cylinder device that is positioned in a constant-temperature bath at 250oC.  The 5.7 kg of steam inside the cylinder expands  reversibly and isothermally to a final pressure of 1.2 MPa. Determine the heat transferred between the constant-temperature bath and the water inside the cylinder as well as the work done by the H2O inside the cylinder during this process.   &lt;br /&gt;&lt;br /&gt;For hints and answers visit: &lt;a href="http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B15"&gt;http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B15&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-2076902973239217364?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B15' title='HW 7B-15 - Heat and Work in an Isothermal Expansion of Steam - 5 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/2076902973239217364/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=2076902973239217364' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2076902973239217364'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2076902973239217364'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/hw-7b-15-heat-and-work-in-isothermal.html' title='HW 7B-15 - Heat and Work in an Isothermal Expansion of Steam - 5 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-4336069654759368686</id><published>2011-03-16T16:20:00.000-07:00</published><updated>2011-03-16T16:20:19.812-07:00</updated><title type='text'>HW 7B-14 - Reversible Compression of Steam in a Piston-and-Cylinder Device - 4 pts</title><content type='html'>Superheated steam is reversibly compressed from 200 kPa to 1.4 MPa in a well-insulated piston-and-cylinder device.  The cylinder initially contains 0.175 m3 of steam at 250°C. Determine the final temperature of the steam and the work done on the steam during this process.   &lt;br /&gt;&lt;br /&gt;For hints and answers visit: &lt;a href="http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B14"&gt;http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B14&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-4336069654759368686?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B14' title='HW 7B-14 - Reversible Compression of Steam in a Piston-and-Cylinder Device - 4 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/4336069654759368686/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=4336069654759368686' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4336069654759368686'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4336069654759368686'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/hw-7b-14-reversible-compression-of.html' title='HW 7B-14 - Reversible Compression of Steam in a Piston-and-Cylinder Device - 4 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-4224225977415771767</id><published>2011-03-16T16:18:00.001-07:00</published><updated>2011-03-16T16:18:53.289-07:00</updated><title type='text'>HW 7B-13 - Minimum Power Required for Adiabatic Compression of R-134a - 4 pts</title><content type='html'>An adiabatic compressor is used to increase the pressure from 105 kPa to 1.25 MPa in a stream of R-134a with a volumetric flow rate of 1800 L/min. Determine the minimum power that must be supplied to the compressor.   &lt;br /&gt;&lt;br /&gt;For hints and answers visit: &lt;a href="http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B13"&gt;http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B13&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-4224225977415771767?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B13' title='HW 7B-13 - Minimum Power Required for Adiabatic Compression of R-134a - 4 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/4224225977415771767/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=4224225977415771767' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4224225977415771767'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4224225977415771767'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/hw-7b-13-minimum-power-required-for.html' title='HW 7B-13 - Minimum Power Required for Adiabatic Compression of R-134a - 4 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-8647941035083571101</id><published>2011-03-16T16:16:00.001-07:00</published><updated>2011-03-16T16:16:46.972-07:00</updated><title type='text'>HW 7B-12 - Reversible Expansion of R-134a in a Piston-and-Cylinder Device - 4 pts</title><content type='html'>The refrigerant R-134a expands reversibly from 2 MPa to 500 kPa in an insulated piston-and-cylinder device.  The cylinder initially contains 15 L of R-134a with a quality of 1.0.  Determine the final temperature of the R-134a in the cylinder and the work done during this process.   &lt;br /&gt;&lt;br /&gt;For hints and answers visit: &lt;a href="http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B12"&gt;http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B12&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-8647941035083571101?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B12' title='HW 7B-12 - Reversible Expansion of R-134a in a Piston-and-Cylinder Device - 4 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/8647941035083571101/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=8647941035083571101' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8647941035083571101'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8647941035083571101'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/hw-7b-12-reversible-expansion-of-r-134a.html' title='HW 7B-12 - Reversible Expansion of R-134a in a Piston-and-Cylinder Device - 4 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-5906865632069762131</id><published>2011-03-16T09:30:00.000-07:00</published><updated>2011-03-16T16:15:01.974-07:00</updated><title type='text'>HW 7B-11 - Entropy Change and Boundary Work for the Isobaric Expansion of Water - 10 pts</title><content type='html'>Electrical work is done by an electrical resistance heater on H2O contained in an insulated piston-and-cylinder device.  The cylinder initially contains 2.4 L of saturated liquid water at a pressure of 500 kPa.  Assuming the piston moves freely, determine the total entropy change of the H2O during a process in which 1875 kJ of heat is transferred into the water.  What is the boundary work for this process?   &lt;br /&gt;&lt;br /&gt;For hints and answers visit: &lt;a href="http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B11"&gt;http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B11&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-5906865632069762131?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B11' title='HW 7B-11 - Entropy Change and Boundary Work for the Isobaric Expansion of Water - 10 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/5906865632069762131/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=5906865632069762131' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5906865632069762131'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5906865632069762131'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/7b-11-entropy-change-and-boundary-work.html' title='HW 7B-11 - Entropy Change and Boundary Work for the Isobaric Expansion of Water - 10 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-5369728688389991064</id><published>2011-03-16T09:28:00.000-07:00</published><updated>2011-03-16T16:14:32.268-07:00</updated><title type='text'>HW 7B-10 - Isobaric Condensation of R-134a - 5 pts</title><content type='html'>The refrigerant R-134a is cooled in a piston-and-cylinder device from 190&amp;deg;F to 75&amp;deg;F. The piston moves freely and the initial pressure is 200 psia.  Determine the specific entropy change of the refrigerant, the work per lbm and heat transfer per lbm during this process.&lt;br /&gt;&lt;br /&gt;For hints and answers visit:&lt;br /&gt;&lt;a href="http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B10"&gt;http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B10&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-5369728688389991064?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B10' title='HW 7B-10 - Isobaric Condensation of R-134a - 5 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/5369728688389991064/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=5369728688389991064' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5369728688389991064'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5369728688389991064'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/7b-10-isobaric-condensation-of-r-134a-5.html' title='HW 7B-10 - Isobaric Condensation of R-134a - 5 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-4975930765551977046</id><published>2011-03-15T12:46:00.001-07:00</published><updated>2011-03-15T12:46:26.338-07:00</updated><title type='text'>HW 7B-9 - Expansion of Water into a Vacuum - 5 pts</title><content type='html'>A rigid tank is divided into two equal parts by a wall. One part of the tank contains 0.74 kg of water at 100 kPa and 25°C.  The other part is a perfect vacuum. The wall is now removed and the water expands to fill the entire tank. A thermocouple indicates that the final equilibrium temperature of the H2O in the tank is 50oC.  Determine the entropy change of water and the total heat transfer to the system during this process.         &lt;br /&gt;&lt;br /&gt;For hints and answers visit:&lt;br /&gt;&lt;a href="http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B9"&gt;http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B9&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-4975930765551977046?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/4975930765551977046/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=4975930765551977046' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4975930765551977046'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4975930765551977046'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/hw-7b-9-expansion-of-water-into-vacuum.html' title='HW 7B-9 - Expansion of Water into a Vacuum - 5 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-946602216956698541</id><published>2011-03-15T12:44:00.001-07:00</published><updated>2011-03-15T12:44:56.520-07:00</updated><title type='text'>HW 7B-8 - Vaporization of Water in a Rigid Tank - 5 pts</title><content type='html'>An electric resistance heater is used to heat the contents of an insulated rigid tank that holds 23.1 kg of H2O.  Initially, the pressure in the tank is 150 kPa and 44% of the mass inside the tank is saturated liquid and the remaining 56% is saturated vapor.  Power is applied to the heater until all of the H2O in the tank is saturated vapor. Determine the entropy change of the H2O and the total of heat transfer during this process.   &lt;br /&gt;&lt;br /&gt;For hints and answers visit:&lt;br /&gt;&lt;a href="http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B8"&gt;http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B8&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-946602216956698541?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B8' title='HW 7B-8 - Vaporization of Water in a Rigid Tank - 5 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/946602216956698541/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=946602216956698541' title='2 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/946602216956698541'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/946602216956698541'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/hw-7b-8-vaporization-of-water-in-rigid.html' title='HW 7B-8 - Vaporization of Water in a Rigid Tank - 5 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-1068319923391872446</id><published>2011-03-15T12:25:00.001-07:00</published><updated>2011-03-15T12:25:51.728-07:00</updated><title type='text'>HW 7B-7 - Isentropic Expansion of R-134a - 4 pts</title><content type='html'>7-38E R-134a expands reversibly and adiabatically in a piston-and-cylinder device from 80 psia and 120°F to 5 psia. If the cylinder contains 17.4 lbm of R-134a, what are the total work done by the system during this process and final temperature of the R-134a ?          &lt;br /&gt;&lt;br /&gt;For hints and answers visit:&lt;br /&gt;&lt;a href="http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B7"&gt;http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B7&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-1068319923391872446?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B7' title='HW 7B-7 - Isentropic Expansion of R-134a - 4 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/1068319923391872446/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=1068319923391872446' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1068319923391872446'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1068319923391872446'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/hw-7b-7-isentropic-expansion-of-r-134a.html' title='HW 7B-7 - Isentropic Expansion of R-134a - 4 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-9114964518446803813</id><published>2011-03-15T12:11:00.000-07:00</published><updated>2011-03-15T12:19:50.800-07:00</updated><title type='text'>HW 7B-6 - Isentropic Compression of Water Vapor - 3 pts</title><content type='html'>An isentropic compressor takes in H2O at 105 kPa and delivers it at 450 kPa. If the temperature of the feed is 180°C, determine the temperature and specific enthalpy of the H2O at the compressor outlet.&lt;br /&gt;&lt;br /&gt;For hints and answers visit:&lt;br /&gt;&lt;a href="http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B6"&gt;http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B6&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-9114964518446803813?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B6' title='HW 7B-6 - Isentropic Compression of Water Vapor - 3 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/9114964518446803813/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=9114964518446803813' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/9114964518446803813'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/9114964518446803813'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/7b-6-isentropic-compression-of-water.html' title='HW 7B-6 - Isentropic Compression of Water Vapor - 3 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-3214211211263602994</id><published>2011-03-15T12:08:00.000-07:00</published><updated>2011-03-15T12:19:36.711-07:00</updated><title type='text'>HW 7B-5 - Entropy Change for an Isobaric Heating Process - 4 pts</title><content type='html'>A piston-and-cylinder device holds 9.7 lbm of water at 250 psia in a volume of 3.6 ft3. Heat is added to the water until the temperature reaches 425oF. During this process, the pressure in the cylinder remains constant because the piston moves freely. Determine the change in the entropy on the water in Btu/oR. &lt;br /&gt;&lt;br /&gt;For hints and answers visit:&lt;br /&gt;&lt;a href="http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B5"&gt;http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B5&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-3214211211263602994?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B5' title='HW 7B-5 - Entropy Change for an Isobaric Heating Process - 4 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/3214211211263602994/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=3214211211263602994' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3214211211263602994'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3214211211263602994'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/7b-5-entropy-change-for-isobaric.html' title='HW 7B-5 - Entropy Change for an Isobaric Heating Process - 4 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-5995656904318637424</id><published>2011-03-09T17:30:00.000-08:00</published><updated>2011-03-15T12:19:24.238-07:00</updated><title type='text'>HW 7B-4 - Power Output of an Isentropic Turbine - 4pts</title><content type='html'>An isentropic turbine produces shaft work as R-134a at 275 psia and 225°F expands through the turbine and exits at 35°F. Assuming the turbine is adiabatic, determine the power output of the turbine per lbm of R-134a. &lt;br /&gt;&lt;br /&gt;For hints and answers visit:&lt;br /&gt;&lt;a href="http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B4"&gt;http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B4&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-5995656904318637424?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B4' title='HW 7B-4 - Power Output of an Isentropic Turbine - 4pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/5995656904318637424/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=5995656904318637424' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5995656904318637424'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5995656904318637424'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/7b-4-power-output-of-isentropic-turbine.html' title='HW 7B-4 - Power Output of an Isentropic Turbine - 4pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-3402332915231325885</id><published>2011-03-09T17:26:00.000-08:00</published><updated>2011-03-15T12:19:08.510-07:00</updated><title type='text'>HW 7B-3 - Entropy Changes Associated with the Evaporator of a Refrigerator - 4 pts</title><content type='html'>A refrigerator using R-134a as the refrigerant removes 200 kJ of heat from its refrigerated space. This heat is absorbed by a mixture of saturated liquid and saturated vapor that enters the evaporator at a pressure of 175 kPa. The R-134a leaves the evaporator as a saturated vapor. Determine... &lt;br /&gt;a.) ... the entropy change of the R-134a, &lt;br /&gt;b.) ... the entropy change of the refrigerated space assuming its temperature remains constant at -10°C, &lt;br /&gt;c.) ... the entropy change of the universe for this process. &lt;br /&gt;&lt;br /&gt;For hints and answers visit:&lt;br /&gt;&lt;a href="http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B3"&gt;http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B3&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-3402332915231325885?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B3' title='HW 7B-3 - Entropy Changes Associated with the Evaporator of a Refrigerator - 4 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/3402332915231325885/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=3402332915231325885' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3402332915231325885'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3402332915231325885'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/7b-3-entropy-changes-associated-with.html' title='HW 7B-3 - Entropy Changes Associated with the Evaporator of a Refrigerator - 4 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-13636097566645076</id><published>2011-03-08T20:20:00.000-08:00</published><updated>2011-03-09T13:20:42.395-08:00</updated><title type='text'>HW 7B-2: Rate of Entropy Increase for a Heat Transfer Process</title><content type='html'>LearnThermo.com Homework Problem 7B-2&lt;br /&gt;&lt;br /&gt;A hot reservoir at 944 K transfers heat to a cold reservoir at 298 K. If the rate of heat transfer is 25 kW,determine the rate at which the entropy of the two reservoirs combined changes (in kW/K) and determine if the second law is satisfied.&lt;br /&gt;&lt;br /&gt;For hints and answers visit:&lt;br /&gt;&lt;a href="http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B2"&gt;http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P2&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-13636097566645076?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P2' title='HW 7B-2: Rate of Entropy Increase for a Heat Transfer Process'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/13636097566645076/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=13636097566645076' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/13636097566645076'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/13636097566645076'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/hw-7b-2-rate-of-entropy-increase-for.html' title='HW 7B-2: Rate of Entropy Increase for a Heat Transfer Process'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-6232417667137416788</id><published>2011-03-08T20:06:00.000-08:00</published><updated>2011-03-09T13:19:05.981-08:00</updated><title type='text'>HW 7B-1: Entropy Change for a Heat Transfer Process</title><content type='html'>LearnThermo.com Homework Problem 7B-1&lt;br /&gt;&lt;br /&gt;Calculate the entropy change of each reservoir when &lt;span style="font-weight:bold;"&gt;1000 kJ&lt;/span&gt; of heat is transferred directly from a hot reservoir at &lt;span style="font-weight:bold;"&gt;1000 K&lt;/span&gt; to a cold reservoir at &lt;span style="font-weight:bold;"&gt;400 K&lt;/span&gt;. Calculate the entropy change of the universe for this process. Does this process violate the principle of increasing entropy?&lt;br /&gt;&lt;br /&gt;For hints and answers visit:&lt;br /&gt;&lt;a href="http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P7B1" target="_new"&gt;http://www.LearnThermo.com/T1-tutorial/ch07/lesson-B/pg20.php#P1&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-6232417667137416788?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/T1-tutorial/ch07/lesson-B/pg20.php' title='HW 7B-1: Entropy Change for a Heat Transfer Process'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/6232417667137416788/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=6232417667137416788' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/6232417667137416788'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/6232417667137416788'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2011/03/hw-7b-1-entropy-change-for-heat.html' title='HW 7B-1: Entropy Change for a Heat Transfer Process'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-8605223122746246949</id><published>2008-12-12T12:15:00.000-08:00</published><updated>2008-12-12T12:27:42.626-08:00</updated><title type='text'>TE 303 - Please give Dr.B some feedback about Thermo-CD</title><content type='html'>Well, the final is over and the holidays are almost here.  I hope you had a great semester and learned a lot.&lt;br /&gt;&lt;br /&gt;If you would be so kind as to share your opinions about Thermo-CD or ideas about how I could improve the program or workbook, that would be greatly appreciated.  You can make your comments anonymously, but they would be more credible if you chose to give your name.  Whether you give your name or not is up to you.  I will NOT contact you in either case.  You can always send questions or comments directly to me if you prefer: Dr.B@LearnThermo.com&lt;br /&gt;&lt;br /&gt;Best of luck to all of you in the years ahead !&lt;br /&gt;&lt;br /&gt;Happy Holidays,&lt;br /&gt;Dr. B&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-8605223122746246949?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - Please give Dr.B some feedback about Thermo-CD'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/8605223122746246949/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=8605223122746246949' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8605223122746246949'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8605223122746246949'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/12/te-303-please-give-drb-some-feedback.html' title='TE 303 - Please give Dr.B some feedback about Thermo-CD'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-8674839281592291076</id><published>2008-12-03T17:17:00.000-08:00</published><updated>2008-12-03T17:19:39.077-08:00</updated><title type='text'>TE 303 - HW #8, P1 - Inventor Claim for Silicon Chip - 20 pts</title><content type='html'>An inventor claims to have created a silicon chip whose surface temperature is no more than 60 °C.  The silicon chip has dimensions of 5 mm on each side with a 1 mm thickness, and is embedded in a ceramic substrate.  At steady state, the chip has an electrical power input of 0.225 W.  The top surface of the chip is exposed to a coolant whose temperature is 20 °C.  The heat transfer coefficient for convection (h) between the coolant and chip is 105 W/m&lt;sup&gt;2&lt;/sup&gt;•K.  Evaluate the inventor's claim using the following:&lt;br /&gt;&lt;br /&gt;a.) First Law Energy Balance, assuming that the heat transfer by conduction between the chip and substrate is negligible.&lt;br /&gt;&lt;br /&gt;b.) Second Law Energy Balance: Calculate entropy generation.&lt;br /&gt;&lt;br /&gt;In your analysis section, be sure to comment on what is the main source of entropy generation in this system.&lt;br /&gt;&lt;br /&gt;No old comments.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-8674839281592291076?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #8, P1 - Inventor Claim for Silicon Chip - 20 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/8674839281592291076/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=8674839281592291076' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8674839281592291076'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8674839281592291076'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/12/te-303-hw-8-p1-inventor-claim-for.html' title='TE 303 - HW #8, P1 - Inventor Claim for Silicon Chip - 20 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-6227258987224549659</id><published>2008-12-03T17:15:00.000-08:00</published><updated>2008-12-03T17:17:19.156-08:00</updated><title type='text'>TE 303 - HW #8, P2 - Maximum Work From an Adiabatic Turbine - 10 pts</title><content type='html'>Steam enters an adiabatic turbine at &lt;span style="font-weight:bold;"&gt;800 psia&lt;/span&gt; and &lt;span style="font-weight:bold;"&gt;900&lt;sup&gt;o&lt;/sup&gt;F&lt;/span&gt; and leaves at a pressure of &lt;span style="font-weight:bold;"&gt;40 psia&lt;/span&gt;.  Determine the maximum amount of work that can be delivered by this turbine.&lt;br /&gt;&lt;br /&gt;No old comments.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-6227258987224549659?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #8, P2 - Maximum Work From an Adiabatic Turbine - 10 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/6227258987224549659/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=6227258987224549659' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/6227258987224549659'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/6227258987224549659'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/12/te-303-hw-8-p2-maximum-work-from.html' title='TE 303 - HW #8, P2 - Maximum Work From an Adiabatic Turbine - 10 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-3942763366708129306</id><published>2008-12-03T17:11:00.000-08:00</published><updated>2008-12-03T17:14:40.645-08:00</updated><title type='text'>TE 303 - HW #8, P3 - Lost Work in a Heat Exchanger - 15 pts</title><content type='html'>A well-insulated shell-and-tube heat exchanger is used to heat water (CP = 4.18 kJ/kg-K) in the tubes from 20oC to 70oC at a rate of 4.5 kg/s.  Heat is supplied by hot oil (CP = 2.30 kJ/kg-K) that enters the shell side at 170oC at a rate of 10 kg/s.  &lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_QYwcFosl4t0/STcuvt7Jk7I/AAAAAAAAAKw/WKnlYZmoeqk/s1600-h/SnT-HEX.png"&gt;&lt;img style="display:block; margin:0px auto 10px; text-align:center;cursor:pointer; cursor:hand;width: 400px; height: 203px;" src="http://1.bp.blogspot.com/_QYwcFosl4t0/STcuvt7Jk7I/AAAAAAAAAKw/WKnlYZmoeqk/s400/SnT-HEX.png" border="0" alt=""id="BLOGGER_PHOTO_ID_5275736885804241842" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;Disregarding any heat loss from the heat exchanger, determine...&lt;br /&gt;&lt;br /&gt;a.) The exit temperature of the oil.&lt;br /&gt;b.) The rate of entropy generation in the heat exchanger.&lt;br /&gt;c.) The rate at which work is lost due to the irreversible nature of heat transfer in this process in kW.  Assume the surroundings are at 20oC.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=7124753858525493724"&gt;3 Old Comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-3942763366708129306?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #8, P3 - Lost Work in a Heat Exchanger - 15 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/3942763366708129306/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=3942763366708129306' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3942763366708129306'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3942763366708129306'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/12/te-303-hw-8-p3-lost-work-in-heat.html' title='TE 303 - HW #8, P3 - Lost Work in a Heat Exchanger - 15 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://1.bp.blogspot.com/_QYwcFosl4t0/STcuvt7Jk7I/AAAAAAAAAKw/WKnlYZmoeqk/s72-c/SnT-HEX.png' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-2739125431426001775</id><published>2008-12-03T17:09:00.000-08:00</published><updated>2008-12-03T17:11:14.451-08:00</updated><title type='text'>TE 303 - HW #8, P4 - Entropy Generation and Lost Work in a Nozzle - 20 pts</title><content type='html'>Oxygen, O2, enters a nozzle operating at steady-state at 3.8 MPa, 387oC and 10 m/s.  At the nozzle exit, the conditions are 150 kPa, 37oC and 790 m/s.&lt;br /&gt;&lt;br /&gt;a.) For a system that encloses the nozzle only, determine the heat transfer (kJ/kg) and the change in specific entropy (kJ/kg-K), both per kg of oxygen flowing through the nozzle.  What additional information would be required to evaluate the rate of entropy production in this process ?&lt;br /&gt;&lt;br /&gt;b.) Using an enlarged system boundary that includes the nozzle and a portion of its immediate surroundings, evaluate the rate of entropy generation (kJ/kg-K) and the rate of lost work (kJ/kg), both per kg of oxygen flowing through the nozzle.  Assume that heat exchange at the enlarged system boundary takes place at the ambient temperature, 20oC.&lt;br /&gt;&lt;br /&gt;Treat O2 as an ideal gas with variable heat capacities.  Verify that the ideal gas assumption is valid.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=3560790198673452586"&gt;2 Old Comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-2739125431426001775?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #8, P4 - Entropy Generation and Lost Work in a Nozzle - 20 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/2739125431426001775/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=2739125431426001775' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2739125431426001775'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2739125431426001775'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/12/te-303-hw-8-p4-entropy-generation-and.html' title='TE 303 - HW #8, P4 - Entropy Generation and Lost Work in a Nozzle - 20 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-7228441290926382283</id><published>2008-12-03T17:03:00.000-08:00</published><updated>2008-12-03T17:08:56.101-08:00</updated><title type='text'>TE 303 - HW #8, P5 - Entropy Balance for a Power Plant - 25 pts</title><content type='html'>The figure to the right shows a simple vapor power plant operating at steady state with water as the working fluid.  Data at key locations are given in the figure.  The mass flow rate of the water circulating through the components is 109 kg/s.  Stray heat transfer and kinetic and potential energy effects can be ignored.&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_QYwcFosl4t0/STctYAPdYkI/AAAAAAAAAKo/rOxt1Wj_zAE/s1600-h/HW8-p5-schematic.png"&gt;&lt;img style="display:block; margin:0px auto 10px; text-align:center;cursor:pointer; cursor:hand;width: 400px; height: 400px;" src="http://3.bp.blogspot.com/_QYwcFosl4t0/STctYAPdYkI/AAAAAAAAAKo/rOxt1Wj_zAE/s400/HW8-p5-schematic.png" border="0" alt=""id="BLOGGER_PHOTO_ID_5275735378892776002" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;Determine the following:&lt;br /&gt;&lt;br /&gt;a.) The mass flow rate of the cooling water, in kg/s.&lt;br /&gt;b.) The thermal efficiency.&lt;br /&gt;c.) The rates of entropy production, each in kW/K, for the turbine, condenser, and pump.&lt;br /&gt;&lt;br /&gt;In your analysis section, place the components in rank order, beginning with the component contributing most to inefficient operation of the overall system.       &lt;br /&gt;       &lt;br /&gt;No old comments.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-7228441290926382283?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #8, P5 - Entropy Balance for a Power Plant - 25 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/7228441290926382283/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=7228441290926382283' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7228441290926382283'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7228441290926382283'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/12/te-303-hw-8-p5-entropy-balance-for.html' title='TE 303 - HW #8, P5 - Entropy Balance for a Power Plant - 25 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_QYwcFosl4t0/STctYAPdYkI/AAAAAAAAAKo/rOxt1Wj_zAE/s72-c/HW8-p5-schematic.png' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-1622336711560232172</id><published>2008-11-13T12:17:00.000-08:00</published><updated>2008-11-13T12:19:54.672-08:00</updated><title type='text'>TE 303 - HW #7, P1 - The Increase of Entropy - 15 pts</title><content type='html'>a.) Will the entropy of steam increase, decrease or remain the same as it flows through a real adiabatic turbine ?&lt;br /&gt;&lt;br /&gt;b.) Will the entropy of the working fluid in an ideal Carnot Cycle increase, decrease or remain the same during the isothermal heat addition process ?&lt;br /&gt;&lt;br /&gt;c.) Steam is accelerated as it flows through a real, adiabatic nozzle. Will the entropy of the steam at the nozzle exit be greater than, equal to or less than the entropy at the nozzle inlet ?&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=8018835513386947471"&gt;3 old comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-1622336711560232172?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #7, P1 - The Increase of Entropy - 15 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/1622336711560232172/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=1622336711560232172' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1622336711560232172'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1622336711560232172'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/11/te-303-hw-7-p1-increase-of-entropy-15.html' title='TE 303 - HW #7, P1 - The Increase of Entropy - 15 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-3111881075454951714</id><published>2008-11-13T12:16:00.000-08:00</published><updated>2008-11-13T12:17:55.094-08:00</updated><title type='text'>TE 303 - HW #7, P2 - Efficiency of an Int. Rev. HE with Multiple Heat Transfers - 10 pts</title><content type='html'>A system executes a power cycle while receiving 750 kJ by heat transfer at 1500 K and rejecting 100 kJ of heat at 500 K. A heat transfer from the system also occurs at 1000 K. There are no other heat transfers. If no internal irreversibilities exist in this system, determine the thermal efficiency of this cycle.&lt;br /&gt;&lt;br /&gt;No old comments.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-3111881075454951714?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #7, P2 - Efficiency of an Int. Rev. HE with Multiple Heat Transfers - 10 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/3111881075454951714/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=3111881075454951714' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3111881075454951714'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3111881075454951714'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/11/te-303-hw-7-p2-efficiency-of-int-rev-he.html' title='TE 303 - HW #7, P2 - Efficiency of an Int. Rev. HE with Multiple Heat Transfers - 10 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-8574970172997439931</id><published>2008-11-13T12:13:00.000-08:00</published><updated>2008-11-13T12:16:18.515-08:00</updated><title type='text'>TE 303 - HW #7, P3 - ΔSSys, ΔSRes, and ΔSUniv, for a H.T. Process - 15 pts</title><content type='html'>During the isothermal heat addition process of a Carnot Cycle, 900 kJ of heat is added to the working fluid from a source at 400oC. Determine:&lt;br /&gt;&lt;br /&gt;a.) the entropy change of the working fluid&lt;br /&gt;b.) the entropy change of the heat source&lt;br /&gt;c.) the total entropy change of the universe for this process.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=5723344926135772857"&gt;1 old comment&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-8574970172997439931?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #7, P3 - ΔSSys, ΔSRes, and ΔSUniv, for a H.T. Process - 15 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/8574970172997439931/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=8574970172997439931' title='3 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8574970172997439931'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8574970172997439931'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/11/te-303-hw-7-p3-ssys-sres-and-suniv-for.html' title='TE 303 - HW #7, P3 - ΔSSys, ΔSRes, and ΔSUniv, for a H.T. Process - 15 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>3</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-2494966996248173630</id><published>2008-11-13T12:11:00.000-08:00</published><updated>2008-11-13T12:13:56.315-08:00</updated><title type='text'>TE 303 - HW #7, P4 - Specific Entropy Change Using Tabluar Data  - 16 pts</title><content type='html'>Using the appropriate table, determine the change in specific entropy in kJ/kg-K for:&lt;br /&gt;&lt;br /&gt;a.) Water: P1 = 10 MPa, T1 = 400 degC and P2 = 10 MPa, T2 = 100 degC.&lt;br /&gt;b.) R-134a: H1 = 211.44 kJ/kg, T1 = - 40 degC and P2 = 5 bar, x2 = 1.0.&lt;br /&gt;c.) Air (IG): T1 = 7 degC, P1 = 2 bar and T2 = 327 degC, P2 = 1 bar.&lt;br /&gt;d.) Hydrogen (H2, IG): T1 = 727 degC, P1 = 1 bar and T2 = 25 degC, P2 = 3 bar.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=376798337802786809"&gt;4 old comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-2494966996248173630?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #7, P4 - Specific Entropy Change Using Tabluar Data  - 16 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/2494966996248173630/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=2494966996248173630' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2494966996248173630'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2494966996248173630'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/11/te-303-hw-7-p4-specific-entropy-change.html' title='TE 303 - HW #7, P4 - Specific Entropy Change Using Tabluar Data  - 16 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-4395694392724975279</id><published>2008-11-13T12:09:00.000-08:00</published><updated>2008-11-13T12:11:15.752-08:00</updated><title type='text'>TE 303 - HW #7, P5 - DSUniv Upon Quenching an Iron Block - 20 pts</title><content type='html'>A 12 kg iron block initially at 350 degC is quenched in an insulated tank that contains 100 kg of water at 22 degC.  Assuming the water that vaporizes during the process condenses back into the liquid phase inside the tank, determine the entropy change of the universe for this process.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=3230074138668826994"&gt;6 old comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-4395694392724975279?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #7, P5 - DSUniv Upon Quenching an Iron Block - 20 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/4395694392724975279/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=4395694392724975279' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4395694392724975279'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4395694392724975279'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/11/te-303-hw-7-p5-dsuniv-upon-quenching.html' title='TE 303 - HW #7, P5 - DSUniv Upon Quenching an Iron Block - 20 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-2356851888044379309</id><published>2008-11-13T12:03:00.000-08:00</published><updated>2008-11-13T12:09:19.640-08:00</updated><title type='text'>TE 303 - HW #7, P6 - DS for Heat Transfer to R-134a in a Rigid Tank - 18 pts</title><content type='html'>A 0.5 m3 rigid tank contains R-134a initially at 200 kPa and 40% quality.  Heat is transferred to the refrigerant from a source at 35oC until the pressure rises to 400 kPa.  Determine…&lt;br /&gt;&lt;br /&gt;a.) The entropy change of the R-134a.&lt;br /&gt;b.) The entropy change of the heat source.&lt;br /&gt;c.) The entropy change of the universe for this process.&lt;br /&gt;  &lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=5698773538548532856"&gt;2 old comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-2356851888044379309?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #7, P6 - DS for Heat Transfer to R-134a in a Rigid Tank - 18 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/2356851888044379309/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=2356851888044379309' title='5 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2356851888044379309'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2356851888044379309'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/11/te-303-hw-7-p6-ds-for-heat-transfer-to.html' title='TE 303 - HW #7, P6 - DS for Heat Transfer to R-134a in a Rigid Tank - 18 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>5</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-5125277656472312459</id><published>2008-11-03T11:58:00.000-08:00</published><updated>2008-11-03T11:59:42.322-08:00</updated><title type='text'>TE 303 - HW #6, P1 - "Show That" Using the K-P Statement of the 2nd Law - 10 pts</title><content type='html'>Using the Kelvin-Planck statement of the 2nd Law, demonstrate the following corollaries.&lt;br /&gt;&lt;br /&gt;a.) The coefficient of performance (COP) of an irreversible heat pump cycle is always less than the COP of a reversible heat pump when both heat pumps exchange heat with the same two thermal reservoirs.&lt;br /&gt;&lt;br /&gt;b.) All reversible heat pump cycles exchanging heat with the same two thermal reservoirs have the same COP.      &lt;br /&gt;       &lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=639979363821954300"&gt;8 Old Comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-5125277656472312459?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #6, P1 - &quot;Show That&quot; Using the K-P Statement of the 2nd Law - 10 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/5125277656472312459/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=5125277656472312459' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5125277656472312459'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5125277656472312459'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/11/te-303-hw-6-p1-show-that-using-k-p.html' title='TE 303 - HW #6, P1 - &quot;Show That&quot; Using the K-P Statement of the 2nd Law - 10 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-2346143509264414106</id><published>2008-11-03T11:57:00.000-08:00</published><updated>2008-11-03T11:58:17.153-08:00</updated><title type='text'>TE 303 - HW #6, P2 - Rev., Irrev. and Impossible Refrigeration Cycles - 16 pts</title><content type='html'>A refrigeration cycle operating between two reservoirs receives QC from a cold reservoir at TC = 250 K and rejects QH to a hot reservoir at TH = 300 K. For each of the following cases, determine whether the cycle is reversible, irreversible or impossible.&lt;br /&gt;&lt;br /&gt;a.) QC = 1000 kJ and Wcycle = 400 kJ&lt;br /&gt;b.) QC = 1500 kJ and QH = 1800 kJ&lt;br /&gt;c.) QH = 1500 kJ and Wcycle = 200 kJ&lt;br /&gt;d.) COP = 4&lt;br /&gt;&lt;br /&gt;No Old Comments.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-2346143509264414106?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #6, P2 - Rev., Irrev. and Impossible Refrigeration Cycles - 16 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/2346143509264414106/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=2346143509264414106' title='3 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2346143509264414106'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2346143509264414106'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/11/te-303-hw-6-p2-rev-irrev-and-impossible.html' title='TE 303 - HW #6, P2 - Rev., Irrev. and Impossible Refrigeration Cycles - 16 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>3</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-5558464143114085021</id><published>2008-11-03T11:54:00.000-08:00</published><updated>2008-11-03T11:56:50.735-08:00</updated><title type='text'>TE 303 - HW #6, P3 - A Reversible HE Used to Drive a Reversible Heat Pump - 10 pts</title><content type='html'>A reversible power cycle receives QH from a reservoir at TH and rejects QC to a reservoir at TC. The work developed by the power cycle is used to drive a reversible heat pump that removes Q'C from a reservoir at T'C and rejects Q'H to a reservoir at T'H.&lt;br /&gt;&lt;br /&gt;a.) Develop an expression for the ratio Q'H / QH in terms of the temperatures of the four reservoirs.&lt;br /&gt;b.) What must be the relationship of the temperatures TH, TC, T'C and T'H for Q'H / QH to exceed a value of 1.0 ?&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=2584859941544839174"&gt;9 Old Comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-5558464143114085021?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #6, P3 - A Reversible HE Used to Drive a Reversible Heat Pump - 10 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/5558464143114085021/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=5558464143114085021' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5558464143114085021'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5558464143114085021'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/11/te-303-hw-6-p3-reversible-he-used-to.html' title='TE 303 - HW #6, P3 - A Reversible HE Used to Drive a Reversible Heat Pump - 10 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-8247129374199316425</id><published>2008-11-03T11:53:00.000-08:00</published><updated>2008-11-03T12:00:46.473-08:00</updated><title type='text'>TE 303 - HW #6, P4 - COMPUTER ANALYSIS: Temp Effects on HE Efficiency - 15 pts</title><content type='html'>A heat engine operates between a source at TH and a sink at TC. Heat is supplied to the heat engine at a steady rate of 1200 kJ/min. Study the effects of TH and TC on the maximum power produced and the maximum cycle efficiency. For TC = 25oC, let TH vary from 300oC to 1000oC. Create plots of Wcycle and ηth as functions of TH. For TH = 550oC, let TC vary from 0oC to 50oC. Create plots of Wcycle and ηth as functions of TC. Discuss the results.  Please note that there will be NO credit given for this problem if it is not solved with Excel.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=7952079770460890548"&gt;6 Old Comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-8247129374199316425?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #6, P4 - COMPUTER ANALYSIS: Temp Effects on HE Efficiency - 15 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/8247129374199316425/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=8247129374199316425' title='4 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8247129374199316425'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8247129374199316425'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/11/te-303-hw-6-p4-computer-analysis-temp.html' title='TE 303 - HW #6, P4 - COMPUTER ANALYSIS: Temp Effects on HE Efficiency - 15 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>4</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-3803109425279199917</id><published>2008-11-03T11:52:00.000-08:00</published><updated>2008-11-03T11:55:02.082-08:00</updated><title type='text'>TE 303 - HW #6, P5 - Maximum Efficiency of an OTEC Power Plant - 8 pts</title><content type='html'>Ocean temperature energy conversion (OTEC) power plants generate power by utilizing the naturally occurring decrease with depth of the temperature ocean water.  Near Florida, the ocean surface temperature is 27oC while at a depth of 700 m the temperature is 7oC.  Determine the maximum possible thermal efficiency for any power cycle operating between these two temperatures.  The thermal efficiency of existing OTEC plants is approximately 2%, so compare this value with your result.  In your analysis section (4 pts), also comment on whether you think that OTEC power plants are viable alternatives to existing power plants.&lt;br /&gt;&lt;br /&gt;No Old Comments.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-3803109425279199917?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #6, P5 - Maximum Efficiency of an OTEC Power Plant - 8 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/3803109425279199917/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=3803109425279199917' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3803109425279199917'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3803109425279199917'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/11/te-303-hw-6-p5-maximum-efficiency-of.html' title='TE 303 - HW #6, P5 - Maximum Efficiency of an OTEC Power Plant - 8 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-3245225775922273659</id><published>2008-11-03T11:49:00.000-08:00</published><updated>2008-11-03T11:52:08.349-08:00</updated><title type='text'>TE 303 - HW #6, P6 - Carnot Gas Power Cycle Analysis - 16 pts</title><content type='html'>One kg of air as an ideal gas executes a Carnot power cycle having a thermal efficiency of 60%.  The heat transfer to the air during the isothermal expansion is 40 kJ.  At the end of the isothermal expansion, the pressure is 5.6 bar and the volume is 0.3 m3.  Determine...&lt;br /&gt;&lt;br /&gt;a.) The maximum and mininmum temperatures for the cycle in Kelvin. &lt;br /&gt;b.) The pressure in bar and volume in m3 at the beginning of the isothermal expansion.&lt;br /&gt;c.) The work and heat transfer for each of the four processes in kJ.&lt;br /&gt;    Assume: CV,air = 0.731 kJ/kg-K(constant).&lt;br /&gt;d.) Sketch the cycle on a PV diagram.      &lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=9007920167847242981"&gt;9 Old Comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-3245225775922273659?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #6, P6 - Carnot Gas Power Cycle Analysis - 16 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/3245225775922273659/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=3245225775922273659' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3245225775922273659'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3245225775922273659'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/11/te-303-hw-6-p6-carnot-gas-power-cycle.html' title='TE 303 - HW #6, P6 - Carnot Gas Power Cycle Analysis - 16 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-7245107321964295011</id><published>2008-11-03T11:47:00.000-08:00</published><updated>2008-11-03T11:49:21.720-08:00</updated><title type='text'>TE 303 - HW #6, P7 - Carnot HE Used to Drive a Carnot Refrigerator - 10 pts</title><content type='html'>A Carnot Heat Engine receives heat from a reservoir at 900oC at a rate of 800 kJ/min and rejects the waste heat to the ambient air at 27oC. The entire work output of the heat engine is used to drive a refrigerator that removes heat from the refrigerated space at -5oC and rejects heat to the same ambient air at 27oC. Determine:&lt;br /&gt;&lt;br /&gt;a.) the maximum rate of heat removal from the refrigerated space&lt;br /&gt;b.) the total rate of heat rejection to the ambient air&lt;br /&gt;&lt;br /&gt;No Old Comments&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-7245107321964295011?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #6, P7 - Carnot HE Used to Drive a Carnot Refrigerator - 10 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/7245107321964295011/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=7245107321964295011' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7245107321964295011'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7245107321964295011'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/11/te-303-hw-6-p7-carnot-he-used-to-drive.html' title='TE 303 - HW #6, P7 - Carnot HE Used to Drive a Carnot Refrigerator - 10 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-1979796386391868112</id><published>2008-11-03T11:45:00.000-08:00</published><updated>2008-11-03T11:47:31.707-08:00</updated><title type='text'>TE 303 - HW #6, P8 - Ammonia Carnot Vapor Refrigeration Cycle - 15 pts</title><content type='html'>Three kg of ammonia executes a Carnot vapor refrigeration cycle.  During the isothermal compression (cooling) step, the ammonia begins as a saturated mixture at 10 bar with a quality of 97% and it is cooled until it is a saturated liquid.  The adiabatic compression step requires 128 kJ/kg of work to increase the pressure from 1.1 bar to 10 bar.&lt;br /&gt;&lt;br /&gt;a.) Sketch the cycle on a PV diagram.&lt;br /&gt;b.) Evaluate the heat and work for each process in kJ.&lt;br /&gt;c.) Evaluate the COP for this cycle.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=359673204680971725"&gt;7 Old Comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-1979796386391868112?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #6, P8 - Ammonia Carnot Vapor Refrigeration Cycle - 15 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/1979796386391868112/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=1979796386391868112' title='4 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1979796386391868112'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1979796386391868112'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/11/te-303-hw-6-p8-ammonia-carnot-vapor.html' title='TE 303 - HW #6, P8 - Ammonia Carnot Vapor Refrigeration Cycle - 15 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>4</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-1408144881786870320</id><published>2008-10-22T19:02:00.000-07:00</published><updated>2008-10-22T19:05:02.354-07:00</updated><title type='text'>TE 303 - HW #5, P1 - Adiabatic Steam Nozzle - 10 pts</title><content type='html'>Steam at 3 MPa and 400oC enters an adiabatic nozzle at a velocity of 40 m/s and leaves at 2.5 MPa and 300 m/s.  Determine…&lt;br /&gt;&lt;br /&gt;a.) The temperature of the steam when it leaves the nozzle.&lt;br /&gt;&lt;br /&gt;b.) The ratio of the inlet cross-sectional area to the outlet cross-sectional area, A1 / A2.&lt;br /&gt;&lt;br /&gt;Assume the process operates at steady-state.&lt;br /&gt;&lt;br /&gt;No old comments.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-1408144881786870320?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #5, P1 - Adiabatic Steam Nozzle - 10 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/1408144881786870320/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=1408144881786870320' title='7 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1408144881786870320'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1408144881786870320'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/10/te-303-hw-5-p1-adiabatic-steam-nozzle.html' title='TE 303 - HW #5, P1 - Adiabatic Steam Nozzle - 10 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>7</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-7644101578020102738</id><published>2008-10-22T19:01:00.000-07:00</published><updated>2008-10-22T19:02:36.210-07:00</updated><title type='text'>TE 303 - HW #5, P2 - Adiabatic Gas Turbine - 10 pts</title><content type='html'>Argon gas enters an adiabatic turbine at 900 kPa and 450oC with a velocity of 80 m/s and leaves at 150 kPa and a velocity of 150 m/s.  The inlet cross-sectional area  is 60 cm2.  If the power output of the turbine is 250 kW, determine the exit temperature of the argon.  The process operates at steady-state and argon behaves as an ideal gas.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=8630210234838922730"&gt;20 Old comments !!&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-7644101578020102738?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #5, P2 - Adiabatic Gas Turbine - 10 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/7644101578020102738/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=7644101578020102738' title='4 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7644101578020102738'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7644101578020102738'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/10/te-303-hw-5-p2-adiabatic-gas-turbine-10.html' title='TE 303 - HW #5, P2 - Adiabatic Gas Turbine - 10 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>4</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-1135491459762723975</id><published>2008-10-22T18:58:00.000-07:00</published><updated>2008-10-22T19:00:14.303-07:00</updated><title type='text'>TE 303 - HW #5, P3 - Effluent Pressure in a Non-Adiabatic Steam Diffuser - 10 pts</title><content type='html'>Steam enters a diffuser at a pressure of 14.7 psia, a temperature of 300oF and a velocity of 500 ft/s.  Steam exits the diffuser as a saturated vapor with negligible kinetic energy.  Heat transfer occurs from the steam to the surroundings at a rate of 19.59 Btu/lbm of flowing steam.  Neglecting potential energy effects, determine the exit pressure in psia.  Assume the diffuser operates at steady-state.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=4540929624294047943"&gt;10 Old comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-1135491459762723975?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #5, P3 - Effluent Pressure in a Non-Adiabatic Steam Diffuser - 10 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/1135491459762723975/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=1135491459762723975' title='5 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1135491459762723975'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1135491459762723975'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/10/te-303-hw-5-p3-effluent-pressure-in-non.html' title='TE 303 - HW #5, P3 - Effluent Pressure in a Non-Adiabatic Steam Diffuser - 10 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>5</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-5952880527222247499</id><published>2008-10-22T18:55:00.000-07:00</published><updated>2008-10-22T19:01:21.100-07:00</updated><title type='text'>TE 303 - HW #5, P4 - Analysis of a Two-Stage, Adiabatic  Turbine - 12 pts</title><content type='html'>A well-insulated two-stage turbine operating at steady-state is shown in the diagram.  Steam enters at 3 MPa and 400oC with a volumetric flow rate of 85 m3/min.  Some steam is extracted from the turbine at a pressure of 0.5 MPa and a temperature of 180oC.  The rest expands to a pressure of 6 kPa and a quality of 90%.  The total power developed by the turbine is 11,400 kW.  Changes in kinetic and potential energies are negligible.  Determine:&lt;br /&gt;&lt;br /&gt;a.) The mass flow rate of the steam at each of the two exits.&lt;br /&gt;&lt;br /&gt;b.) The diameter in meters of the duct through which the 0.5 MPa steam is extracted if the velocity there is 20 m/s.&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_QYwcFosl4t0/SP_Z8w0aK5I/AAAAAAAAAJo/2rhAQmxpsHU/s1600-h/hw5-p4.png"&gt;&lt;img style="display:block; margin:0px auto 10px; text-align:center;cursor:pointer; cursor:hand;width: 400px; height: 300px;" src="http://3.bp.blogspot.com/_QYwcFosl4t0/SP_Z8w0aK5I/AAAAAAAAAJo/2rhAQmxpsHU/s400/hw5-p4.png" border="0" alt=""id="BLOGGER_PHOTO_ID_5260162527712127890" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=7393296422754039391"&gt;6 Old comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-5952880527222247499?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #5, P4 - Analysis of a Two-Stage, Adiabatic  Turbine - 12 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/5952880527222247499/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=5952880527222247499' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5952880527222247499'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5952880527222247499'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/10/te-303-hw-5-p4-analysis-of-two-stage.html' title='TE 303 - HW #5, P4 - Analysis of a Two-Stage, Adiabatic  Turbine - 12 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_QYwcFosl4t0/SP_Z8w0aK5I/AAAAAAAAAJo/2rhAQmxpsHU/s72-c/hw5-p4.png' height='72' width='72'/><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-2714577746060946725</id><published>2008-10-22T18:53:00.000-07:00</published><updated>2008-10-22T18:55:50.898-07:00</updated><title type='text'>TE 303 - HW #5, P5 - COMPUTER ANALYSIS: Adiabatic Steam De-Superheater - 15 pts</title><content type='html'>As shown in the diagram, 15 kg/s of steam enters a de-superheater operating at steady-state at 30 bar and 320oC where it is mixed with liquid water at 25 bar  and temperature T3 to produce saturated vapor at 20 bar.  Heat transfer between the device and its surroundings and changes in kinetic and potential energies are negligible.&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_QYwcFosl4t0/SP_ZcRDYFrI/AAAAAAAAAJg/ouasfBWAT7o/s1600-h/hw5-p5.jpg"&gt;&lt;img style="display:block; margin:0px auto 10px; text-align:center;cursor:pointer; cursor:hand;width: 400px; height: 300px;" src="http://3.bp.blogspot.com/_QYwcFosl4t0/SP_ZcRDYFrI/AAAAAAAAAJg/ouasfBWAT7o/s400/hw5-p5.jpg" border="0" alt=""id="BLOGGER_PHOTO_ID_5260161969429157554" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;a.) If T3 = 200oC, determine the mass flow rate of stream 3.&lt;br /&gt;&lt;br /&gt;b.) Plot the mass flow rate of stream 3 in kg/s as a function of T3 as T3 ranges from 20 to 220oC.&lt;br /&gt;&lt;br /&gt;Note that the use of ThermalFluids will avoid the need to interpolate in this problem!&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=7217899328246478144"&gt;4 Old comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-2714577746060946725?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #5, P5 - COMPUTER ANALYSIS: Adiabatic Steam De-Superheater - 15 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/2714577746060946725/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=2714577746060946725' title='2 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2714577746060946725'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2714577746060946725'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/10/te-303-hw-5-p5-computer-analysis.html' title='TE 303 - HW #5, P5 - COMPUTER ANALYSIS: Adiabatic Steam De-Superheater - 15 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_QYwcFosl4t0/SP_ZcRDYFrI/AAAAAAAAAJg/ouasfBWAT7o/s72-c/hw5-p5.jpg' height='72' width='72'/><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-8999467246419012955</id><published>2008-10-22T18:50:00.000-07:00</published><updated>2008-10-22T18:52:58.029-07:00</updated><title type='text'>TE 303 - HW #5, P6 - Pump Horsepower Requirment - 10 pts</title><content type='html'>The pump shown here increases the pressure in liquid water from 200 to 4000 kPa.&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_QYwcFosl4t0/SP_YpBztf4I/AAAAAAAAAJY/asD3Yc4K3h8/s1600-h/hw5-p6.png"&gt;&lt;img style="display:block; margin:0px auto 10px; text-align:center;cursor:pointer; cursor:hand;width: 290px; height: 90px;" src="http://3.bp.blogspot.com/_QYwcFosl4t0/SP_YpBztf4I/AAAAAAAAAJY/asD3Yc4K3h8/s400/hw5-p6.png" border="0" alt=""id="BLOGGER_PHOTO_ID_5260161089163591554" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;What is the minimum horsepower motor required to drive the pump for a flow rate of 0.1 m3/s ?&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=841155316902614687"&gt;8 Old comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-8999467246419012955?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #5, P6 - Pump Horsepower Requirment - 10 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/8999467246419012955/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=8999467246419012955' title='2 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8999467246419012955'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8999467246419012955'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/10/te-303-hw-5-p6-pump-horsepower.html' title='TE 303 - HW #5, P6 - Pump Horsepower Requirment - 10 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_QYwcFosl4t0/SP_YpBztf4I/AAAAAAAAAJY/asD3Yc4K3h8/s72-c/hw5-p6.png' height='72' width='72'/><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-4415553149370973866</id><published>2008-10-22T18:46:00.000-07:00</published><updated>2008-10-22T18:50:41.002-07:00</updated><title type='text'>TE 303 - HW #5, P7 - Waste Heat Steam Generator - 15 pts</title><content type='html'>At steady-state, water enters the waste heat recovery steam generator shown in the diagram at 42 psia and 220oF and exits at 40 psia and 320oF.  The steam is then fed into a turbine from which it exits at 1 psia and a quality of 90%.&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_QYwcFosl4t0/SP_X7yD3qiI/AAAAAAAAAJQ/QFHmTlfCMdY/s1600-h/hw5-p7.jpg"&gt;&lt;img style="display:block; margin:0px auto 10px; text-align:center;cursor:pointer; cursor:hand;width: 400px; height: 300px;" src="http://4.bp.blogspot.com/_QYwcFosl4t0/SP_X7yD3qiI/AAAAAAAAAJQ/QFHmTlfCMdY/s400/hw5-p7.jpg" border="0" alt=""id="BLOGGER_PHOTO_ID_5260160311842286114" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;Air from an oven exhaust enters the steam generator at 360oF and 1 atm with a volumetric flow rate of 3000 ft3/min and exits at 280oF and 1 atm.  Ignore all heat exchange with the surroundings and any changes in potential and kinetic energies.  Determine the power developed by the turbine in horsepower.&lt;br /&gt;&lt;br /&gt;CP,air = 7.05 Btu/lbmole-oF.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=6910552630540188504"&gt;9 Old comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-4415553149370973866?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #5, P7 - Waste Heat Steam Generator - 15 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/4415553149370973866/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=4415553149370973866' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4415553149370973866'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4415553149370973866'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/10/te-303-hw-5-p7-waste-heat-steam.html' title='TE 303 - HW #5, P7 - Waste Heat Steam Generator - 15 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://4.bp.blogspot.com/_QYwcFosl4t0/SP_X7yD3qiI/AAAAAAAAAJQ/QFHmTlfCMdY/s72-c/hw5-p7.jpg' height='72' width='72'/><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-6617357195309398940</id><published>2008-10-22T18:42:00.000-07:00</published><updated>2008-10-22T18:46:23.339-07:00</updated><title type='text'>TE 303 - HW #5, P8 - Transient Heating of an Office Space - 18 pts</title><content type='html'>The air supply to a 20000 ft3 office has been shut off overnight to conserve utilities, and the room temperature has dropped to 40oF.  In the morning, a worker resets the thermostat to 70oF, and 200 ft3/min of air at 120oF begins to flow into the office through a heating duct.  The air is well-mixed within the room and an  equal mass flow of air at room temperature is withdrawn through a return duct.  The air pressure is essentially 1 atm everywhere.  Ignoring heat exchange with the surroundings, as well as any changes in kinetic or potential energies, estimate how long it takes for the room temperature to reach 70oF.  Assume g = 1.4 for the air.&lt;br /&gt;&lt;br /&gt;HINTS :&lt;br /&gt;This is a transient or unsteady process because helium enters the system (the balloon). Assume the He behaves as an ideal gas, but check to see if this is a good assumption. Use the IG EOS to determine the initial mass of He in the balloon. After you determine V2, calculating Wb is easy ! Then, simultaneously solve two equations in two unknowns. The equations are: the IG EOS applied to the final state of the balloon and the transient form of the 1st Law applied to this process. The two unknowns are: T2, mHe,2 .&lt;br /&gt;The catch is that we must determine values for U1, U2 and Hin. These are NOT ΔU's and ΔH's but real U's and H's. In order to do this (just like the steam tables) we MUST choose a reference state. A reference state is a T, P and phase at which YOU choose to make EITHER U or H zero kJ/kg. I want you to use a reference state of U = 0 for He gas at 22 oC and 100 kPa. The P doesn't actually matter because He is treated as an IG in this problem so U and H are not functions of P anyway.&lt;br /&gt;&lt;br /&gt;Once you have a ref state, use a Hypothetical Process Path from the ref state to states 1, 2 and inlet to evaluate U1, U2 and Hin using the IG EOS and CV and CP given in the problem.&lt;br /&gt;&lt;br /&gt;For He, use: CP = 5.1926 kJ/kg-K and CV = 3.1156 kJ/kg-K.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=1002822739110760063"&gt;11 Old comments !&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-6617357195309398940?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #5, P8 - Transient Heating of an Office Space - 18 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/6617357195309398940/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=6617357195309398940' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/6617357195309398940'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/6617357195309398940'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/10/te-303-hw-5-p8-transient-heating-of.html' title='TE 303 - HW #5, P8 - Transient Heating of an Office Space - 18 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-4133214584659581243</id><published>2008-09-30T12:36:00.000-07:00</published><updated>2008-10-01T16:35:34.659-07:00</updated><title type='text'>TE 303 - HW #4, P1 - Compression of Cooling Air by a Linear Spring - 15 pts</title><content type='html'>Warm air is conatined in a piston-and-cylinder device oriented horizontally, as shown below.  The air cools slowly from an initial volume of 0.003 m3 to a final volume of 0.002 m3.  During this process, the spring exerts a force that varies linearly from 900 N to a final value of zero N.  The atmospheric pressure is 100 kPa and the area of the piston face is 0.018 m2.  Friction between the piston and cylinder wall can be neglected because the process occurs so slowly.  For the air, determine the initial and final pressures in kPa and the boundary work for the process in kJ.&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_QYwcFosl4t0/SOJ__4niMII/AAAAAAAAAJE/iuvq9w8f6EA/s1600-h/hw4-p1.png"&gt;&lt;img style="display:block; margin:0px auto 10px; text-align:center;cursor:pointer; cursor:hand;" src="http://2.bp.blogspot.com/_QYwcFosl4t0/SOJ__4niMII/AAAAAAAAAJE/iuvq9w8f6EA/s400/hw4-p1.png" border="0" alt=""id="BLOGGER_PHOTO_ID_5251900850974109826" /&gt;&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-4133214584659581243?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #4, P1 - Compression of Cooling Air by a Linear Spring - 15 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/4133214584659581243/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=4133214584659581243' title='11 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4133214584659581243'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4133214584659581243'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-4-p1-compression-of-cooling.html' title='TE 303 - HW #4, P1 - Compression of Cooling Air by a Linear Spring - 15 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://2.bp.blogspot.com/_QYwcFosl4t0/SOJ__4niMII/AAAAAAAAAJE/iuvq9w8f6EA/s72-c/hw4-p1.png' height='72' width='72'/><thr:total>11</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-3653778488815967282</id><published>2008-09-30T12:33:00.000-07:00</published><updated>2008-09-30T12:45:29.658-07:00</updated><title type='text'>TE 303 - HW #4, P2 - Work and Heat Transfer for a Closed, 3-Step Cycle - 15 pts</title><content type='html'>A closed system undergoes a thermodynamic cycle consisting of the following processes:&lt;br /&gt;&lt;br /&gt;Process 1-2: Adiabatic compression from P1 = 50 psia, V1 = 3.0 ft3 to V2 = 1 ft3 along a path described by :&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_QYwcFosl4t0/SOJ_fPGB3eI/AAAAAAAAAI8/qk5K1g-WnwM/s1600-h/HW4-P2-eqn.png"&gt;&lt;img style="display:block; margin:0px auto 10px; text-align:center;cursor:pointer; cursor:hand;" src="http://2.bp.blogspot.com/_QYwcFosl4t0/SOJ_fPGB3eI/AAAAAAAAAI8/qk5K1g-WnwM/s400/HW4-P2-eqn.png" border="0" alt=""id="BLOGGER_PHOTO_ID_5251900290071911906" /&gt;&lt;/a&gt;&lt;br /&gt;      &lt;br /&gt;Process 2-3: Constant volume.      &lt;br /&gt;Process 3-1: Constant pressure with U1 - U3 = 46.7 Btu.&lt;br /&gt;      &lt;br /&gt;There are no significant changes in kinetic or potential energies in any of the processes.&lt;br /&gt;a.) Sketch this cycle on a PV Diagram.&lt;br /&gt;b.) Calculate the net work for the cycle in Btu.&lt;br /&gt;c.) Calculate the heat transfer for process 2-3.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=1250831484099511670"&gt;6 Old Comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-3653778488815967282?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #4, P2 - Work and Heat Transfer for a Closed, 3-Step Cycle - 15 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/3653778488815967282/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=3653778488815967282' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3653778488815967282'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3653778488815967282'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-4-p2-work-and-heat-transfer.html' title='TE 303 - HW #4, P2 - Work and Heat Transfer for a Closed, 3-Step Cycle - 15 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://2.bp.blogspot.com/_QYwcFosl4t0/SOJ_fPGB3eI/AAAAAAAAAI8/qk5K1g-WnwM/s72-c/HW4-P2-eqn.png' height='72' width='72'/><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-1624396487591205413</id><published>2008-09-30T12:27:00.000-07:00</published><updated>2008-09-30T12:33:19.236-07:00</updated><title type='text'>TE 303 - HW #4, P3 - COMPUTER ANALYSIS: P-V Data  - 20 pts</title><content type='html'>Measured data for pressure versus volume during the expansion of gases within the cylinder of an internal combustion engine are given in the table below:&lt;br /&gt;&lt;br /&gt;Data Point V (cm^3) P (bar)    &lt;br /&gt; 1 300         15    &lt;br /&gt; 2 361         12    &lt;br /&gt; 3 459         9    &lt;br /&gt; 4 644         6    &lt;br /&gt; 5 903         4    &lt;br /&gt; 6 1608         2    &lt;br /&gt;       &lt;br /&gt;Using data from the table and using EXCEL, complete the following:       &lt;br /&gt;(a)  Determine the value of d such that the data are fit by an equation of the form PVd = constant.  (HINT: take the log of both sides and rearrange into a linear equation.)    You are expected to extract the value of d from either doing a curve fit with something like least squares, or from the slope or intercept function in Excel for the appropriate graph.&lt;br /&gt;      &lt;br /&gt;(b)   Evaluate analytically the work done by the gases, in kJ, using the appropriate equation from class along with the result from (a).&lt;br /&gt;      &lt;br /&gt;(c)  Using numerical integration of the data, evaluate the work done by the gases, in kJ (NOTE: Be careful about converting your units!).  A common numerical integration method is the Trapezoidal Rule for Unevenly Spaced Data.  Using this method, you can approximate the integral in the following way:      &lt;br /&gt;    &lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_QYwcFosl4t0/SOJ-rq_qN4I/AAAAAAAAAI0/eDzCvBc4cZE/s1600-h/HW4-P3-eqn.png"&gt;&lt;img style="display:block; margin:0px auto 10px; text-align:center;cursor:pointer; cursor:hand;" src="http://1.bp.blogspot.com/_QYwcFosl4t0/SOJ-rq_qN4I/AAAAAAAAAI0/eDzCvBc4cZE/s400/HW4-P3-eqn.png" border="0" alt=""id="BLOGGER_PHOTO_ID_5251899404208191362" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;where Ai is the area of each   rectangular interval, and n is the number of rectangular intervals.&lt;br /&gt;&lt;br /&gt;For more information on the Trapezoidal Rule, please see the following website:  http://oregonstate.edu/~haggertr/487/integrate.htm&lt;br /&gt;&lt;br /&gt;For the "analysis" section of your Engineering Model, be sure to compare the different methods for estimating the work used in parts (b) and (c).&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-1624396487591205413?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #4, P3 - COMPUTER ANALYSIS: P-V Data  - 20 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/1624396487591205413/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=1624396487591205413' title='10 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1624396487591205413'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1624396487591205413'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-4-p3-computer-analysis-p-v.html' title='TE 303 - HW #4, P3 - COMPUTER ANALYSIS: P-V Data  - 20 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://1.bp.blogspot.com/_QYwcFosl4t0/SOJ-rq_qN4I/AAAAAAAAAI0/eDzCvBc4cZE/s72-c/HW4-P3-eqn.png' height='72' width='72'/><thr:total>10</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-6878286178858086663</id><published>2008-09-30T12:26:00.000-07:00</published><updated>2008-09-30T12:43:30.871-07:00</updated><title type='text'>TE 303 - HW #4, P4 - Combined Convection and Radiation Heat Loss - 8 pts</title><content type='html'>A 3.0 m2 hot black surface at 80oC is losing heat to the surrounding air at 25oC by convection with a convection heat transfer coefficient of 12 W/m2-oC, and by radiation to the surrounding surfaces at 15oC.  Determine the total rate of heat loss from the surface in W.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=6443521547783880315"&gt;2 Old Comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-6878286178858086663?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #4, P4 - Combined Convection and Radiation Heat Loss - 8 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/6878286178858086663/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=6878286178858086663' title='3 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/6878286178858086663'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/6878286178858086663'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-4-p4-combined-convection-and.html' title='TE 303 - HW #4, P4 - Combined Convection and Radiation Heat Loss - 8 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>3</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-3191830720188686546</id><published>2008-09-30T12:25:00.000-07:00</published><updated>2008-09-30T12:42:36.800-07:00</updated><title type='text'>TE 303 - HW #4, P5 - Minimum Insulation Thickness for a Hot Surface - 10 pts</title><content type='html'>A flat surface is covered with insulation with a thermal conductivity of 0.08 W/m-K.  The temperature at the interface between the surface and the insulation is 300oC.  The outside of the insulation is exposed to air at 30oC and the convection heat transfer coefficient between the insulation and the air is 10 W/m2-K.  Ignoring radiation heat transfer, determine the minimum thickness of the insulation, in m, such that the outside surface of the insulation is not hotter than 60oC at steady-state.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=8311874391640691702"&gt;2 Old Comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-3191830720188686546?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #4, P5 - Minimum Insulation Thickness for a Hot Surface - 10 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/3191830720188686546/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=3191830720188686546' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3191830720188686546'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3191830720188686546'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-4-p5-minimum-insulation.html' title='TE 303 - HW #4, P5 - Minimum Insulation Thickness for a Hot Surface - 10 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-297567241370168274</id><published>2008-09-30T12:20:00.001-07:00</published><updated>2008-09-30T12:41:25.336-07:00</updated><title type='text'>TE 303 - HW #4, P6 - Isobaric Expansion of R-134a - 15 pts</title><content type='html'>A piston-and-cylinder device with a set of stops contains 10 kg of R-134a.  Initially, 8.0 kg of the refrigerant is in the liquid phase and the temperature is -8.0oC.  Now, heat is transferred slowly into the refrigerant until the piston hits the stops.  At this point, the volume is 400 L.  Determine:&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_QYwcFosl4t0/SOJ8UvhrUSI/AAAAAAAAAIs/cixFmy0TxH0/s1600-h/hw4-p6.png"&gt;&lt;img style="float:left; margin:0 10px 10px 0;cursor:pointer; cursor:hand;" src="http://2.bp.blogspot.com/_QYwcFosl4t0/SOJ8UvhrUSI/AAAAAAAAAIs/cixFmy0TxH0/s400/hw4-p6.png" border="0" alt=""id="BLOGGER_PHOTO_ID_5251896811264364834" /&gt;&lt;/a&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br&gt;&lt;br /&gt;&lt;p&gt;&lt;br /&gt;a.) The temperature of the R-134a when the piston reaches the stops.&lt;br /&gt;b.) The boundary work done during this expansion process.&lt;br /&gt;c.) The heat transfer during this expansion process.&lt;br /&gt;d.) Show this process on a PV Diagram.&lt;/p&gt;&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=2616804812893479230"&gt;13 Old Comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-297567241370168274?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #4, P6 - Isobaric Expansion of R-134a - 15 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/297567241370168274/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=297567241370168274' title='3 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/297567241370168274'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/297567241370168274'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-4-p6-isobaric-expansion-of-r_30.html' title='TE 303 - HW #4, P6 - Isobaric Expansion of R-134a - 15 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://2.bp.blogspot.com/_QYwcFosl4t0/SOJ8UvhrUSI/AAAAAAAAAIs/cixFmy0TxH0/s72-c/hw4-p6.png' height='72' width='72'/><thr:total>3</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-9065459457728204825</id><published>2008-09-30T12:17:00.000-07:00</published><updated>2008-09-30T12:20:42.264-07:00</updated><title type='text'>TE 303 - HW #4, P7 - 1st Law Analysis of Steam in a Closed System - 8 pts</title><content type='html'>As shown in the figure below, 5.0 kg of steam contained within a piston-and-cylinder device undergoes an expansion from state 1 where the specific internal energy is 2709.9 kJ/kg to state 2 where the specific internal energy is 2659.6 kJ/kg.  During the process, there is heat transefer to the steam with a magnitude of 80 kJ.  Also, a paddle wheel transfers energy to the steam by work in the amount of 18.5 kJ.  There is no significant change in the kinetic or gravitational potential energies of the steam.  Determine the work done by the steam on the piston during the process in kJ.&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_QYwcFosl4t0/SOJ7vkmFMOI/AAAAAAAAAIk/WItYBCuyVZE/s1600-h/hw4-p7.png"&gt;&lt;img style="float:left; margin:0 10px 10px 0;cursor:pointer; cursor:hand;" src="http://4.bp.blogspot.com/_QYwcFosl4t0/SOJ7vkmFMOI/AAAAAAAAAIk/WItYBCuyVZE/s400/hw4-p7.png" border="0" alt=""id="BLOGGER_PHOTO_ID_5251896172674887906" /&gt;&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-9065459457728204825?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #4, P7 - 1st Law Analysis of Steam in a Closed System - 8 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/9065459457728204825/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=9065459457728204825' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/9065459457728204825'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/9065459457728204825'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-3-p7-1st-law-analysis-of.html' title='TE 303 - HW #4, P7 - 1st Law Analysis of Steam in a Closed System - 8 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://4.bp.blogspot.com/_QYwcFosl4t0/SOJ7vkmFMOI/AAAAAAAAAIk/WItYBCuyVZE/s72-c/hw4-p7.png' height='72' width='72'/><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-8998513865869375114</id><published>2008-09-30T12:13:00.000-07:00</published><updated>2008-09-30T12:14:36.720-07:00</updated><title type='text'>TE 303 - HW #4, P8 - Work for a "Non-Standard" P-V Relationship - 9 pts</title><content type='html'>Oxygen (O2) gas within a piston-cylinder assembly undergoes an expansion from a volume V1 = 0.01 m3 to a volume  V2 = 0.03 m3.  The relationship between pressure and volume during the process is P = AV-1 + B, where A = 0.06 bar m3, and B = 3.0 bar.  For the O2 , determine the following:&lt;br /&gt;&lt;br /&gt;a.) The initial and final pressures, each in bar.&lt;br /&gt;b.) The work, in kJ.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-8998513865869375114?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #4, P8 - Work for a &quot;Non-Standard&quot; P-V Relationship - 9 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/8998513865869375114/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=8998513865869375114' title='5 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8998513865869375114'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8998513865869375114'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-4-p8-work-for-non-standard-p.html' title='TE 303 - HW #4, P8 - Work for a &quot;Non-Standard&quot; P-V Relationship - 9 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>5</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-1421852923428252093</id><published>2008-09-17T20:26:00.000-07:00</published><updated>2008-09-17T20:57:07.986-07:00</updated><title type='text'>TE 303 - HW #3, P1 - Steam NIST / TFT Fundamentals - 8 pts</title><content type='html'>Complete the following table for water (revisited from HW2) using either the NIST Webbook or the Thermal Fluids Excel Plug in.  Be sure to cite which one that you used.  Your grade will be based mostly on the use of technology, not on the answers.  Your solution must be different than your solution from HW2.&lt;br /&gt;&lt;br /&gt;T(oC) P(kPa) H(kJ/kg) x(kg vap/kg) Phase Description&lt;br /&gt;&lt;br /&gt;a.) P = 200 kPa and x = 0.7 kg vap/kg&lt;br /&gt;b.) T = 140 degC and H = 1800 kJ/kg&lt;br /&gt;c.) P = 950 kPa and x = 0 kg vap/kg&lt;br /&gt;d.) T = 80 degC and P = 500 kPa&lt;br /&gt;e.) P = 800 kPa and H = 3161.7 kJ/kg&lt;br /&gt;&lt;br /&gt;No Old Comments.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-1421852923428252093?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #3, P1 - Steam NIST / TFT Fundamentals - 8 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/1421852923428252093/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=1421852923428252093' title='5 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1421852923428252093'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1421852923428252093'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-3-p1-steam-nist-tft.html' title='TE 303 - HW #3, P1 - Steam NIST / TFT Fundamentals - 8 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>5</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-4407089769211515891</id><published>2008-09-17T20:24:00.000-07:00</published><updated>2008-09-24T12:57:50.848-07:00</updated><title type='text'>TE 303 - HW #3, P2 - R-134a NIST/TFT Fundamentals - 12 pts</title><content type='html'>Complete the following table for R-134a(revisited from HW2) using either the NIST Webbook or the Thermal Fluids Excel Plug in.  Be sure to cite which one that you used.  Your grade will be based mostly on the use of technology, not on the answers.  Your solution must be different than your solution from HW2.&lt;br /&gt;&lt;br /&gt;Include an analysis of a comparison of this solution (including Problem 1) to using traditional data tables in HW2.  Are the values comparable?  Is interpolation still necessary?  Which method is more efficient?  Explain.  (4 pts)&lt;br /&gt;&lt;br /&gt;T(oF) P(psia) U(Btu/lbm) x(lbm vap/lbm) Phase Description&lt;br /&gt;&lt;br /&gt;a.) P = 80 psia and U = 126 Btu/lbm&lt;br /&gt;b.) T = 15 degF and x = 0.6 lbm vap/lbm&lt;br /&gt;c.) T = 10 degF and P = 70 psia&lt;br /&gt;d.) P = 180 psia and U = 226 Btu/lbm&lt;br /&gt;e.) T = 110 degF and x = 1.0 lbm vap/lbm&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=661045210481409784"&gt;3 Old Comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-4407089769211515891?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #3, P2 - R-134a NIST/TFT Fundamentals - 12 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/4407089769211515891/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=4407089769211515891' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4407089769211515891'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4407089769211515891'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-3-p2-problem-title-here-12.html' title='TE 303 - HW #3, P2 - R-134a NIST/TFT Fundamentals - 12 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-8323291300008673067</id><published>2008-09-17T20:20:00.000-07:00</published><updated>2008-09-17T20:51:55.199-07:00</updated><title type='text'>TE 303 - HW #3, P3 - Determining DH Using Heat Capacity Polynomials - 16 pts</title><content type='html'>Determine the change in the specific enthalpy of nitrogen (N2), in kJ/kg, as it is heated from 600 to 1500 K, using:&lt;br /&gt;&lt;br /&gt;a.) The empirical specific heat equation (Shomate Eqn) from the NIST Website.&lt;br /&gt;b.) "The CoP value at the average temperature. (Use the heat capacity polynomial to determine this CoP value.)&lt;br /&gt;c.) The CoP value at room temperature, 25oC. (Use the heat capacity polynomial to determine this CoP value.)&lt;br /&gt;&lt;br /&gt;In your analysis, be sure to include a comparison of these three methods. (4 pts)&lt;br /&gt;HINT: You can get the parameters for the Shomate Equation from the NIST Webbook by searching by "name", then click on "gas phase data", then "gas phase thermochemistry data".  Part (a) Integral of CoP with respect to T...just like in class. Parts (b) and (c) are easier. Just evaluate CoP at ONE T and then assume CoP has this value and it is constant.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=1750111542217065334"&gt;8 Old Comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-8323291300008673067?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #3, P3 - Determining DH Using Heat Capacity Polynomials - 16 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/8323291300008673067/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=8323291300008673067' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8323291300008673067'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8323291300008673067'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-3-p3-determining-dh-using.html' title='TE 303 - HW #3, P3 - Determining DH Using Heat Capacity Polynomials - 16 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-7974681967594393554</id><published>2008-09-17T20:16:00.000-07:00</published><updated>2008-09-17T20:53:16.441-07:00</updated><title type='text'>TE 303 - HW #3, P4 - Determining DU Using Heat Capacity Polynomials - 16 pts</title><content type='html'>Determine the change in the specific internal energy of hydrogen (H2), in kJ/kg, as it is heated from 400 to 1000 K, using:&lt;br /&gt;&lt;br /&gt;a.) The empirical specific heat equation (Shomate Eqn) from the NIST Website.&lt;br /&gt;b.) The CoV value at the average temperature. (Use the heat capacity polynomial to determine this CoV value.)&lt;br /&gt;c.) The CoV value at room temperature, 25oC. (Use the heat capacity polynomial to determine this CoV value.)      &lt;br /&gt;       &lt;br /&gt;In your analysis, be sure to include a comparison of these three methods. (4 pts)       &lt;br /&gt;HINT: To start this problem, copy your spreadsheet from #3 after you solved it, and then modify it for this problem.  Some of the calculations are the same! Part (a) Integral of CoV with respect to T...just like in class. Parts (b) and (c) are easier. Just evaluate CoV at ONE T and then assume CoV has this value and it is constant. Remember that you are using the IDEAL GAS heat capacity.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=1436891265829478311"&gt;3 Old Comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-7974681967594393554?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #3, P4 - Determining DU Using Heat Capacity Polynomials - 16 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/7974681967594393554/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=7974681967594393554' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7974681967594393554'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7974681967594393554'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-3-p4-determining-du-using.html' title='TE 303 - HW #3, P4 - Determining DU Using Heat Capacity Polynomials - 16 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-4758755169790282873</id><published>2008-09-17T20:12:00.000-07:00</published><updated>2008-09-17T20:54:27.761-07:00</updated><title type='text'>TE 303 - HW #3, P5 - Clapeyron &amp; Clausius-Clapeyron Equations - 16 pts</title><content type='html'>Estimate the latent heat of vaporization, in Btu/lbm, of ammonia at -10oF using:&lt;br /&gt;&lt;br /&gt;a.) The Clapeyron equation&lt;br /&gt;b.) The Clausius-Clapeyron equation&lt;br /&gt;c.) The ammonia tables&lt;br /&gt;&lt;br /&gt;In your analysis, be sure to include a comparison of these three methods and propose a reason for any significant differences. (4 pts)&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=4195572522767018112"&gt;13 Old Comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-4758755169790282873?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #3, P5 - Clapeyron &amp; Clausius-Clapeyron Equations - 16 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/4758755169790282873/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=4758755169790282873' title='12 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4758755169790282873'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4758755169790282873'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-3-p5-clapeyron-clausius.html' title='TE 303 - HW #3, P5 - Clapeyron &amp; Clausius-Clapeyron Equations - 16 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>12</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-4312554622285303202</id><published>2008-09-17T20:06:00.000-07:00</published><updated>2008-09-17T20:55:13.088-07:00</updated><title type='text'>TE 303 - HW #3, P6 - Hypothetical Process Paths and the Latent Heat of Vaporization - 24 pts</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_QYwcFosl4t0/SNHG1zhAcCI/AAAAAAAAAIc/GEG6J6vShx8/s1600-h/sp07-hw3-p6.gif"&gt;&lt;img style="float:left; margin:0 10px 10px 0;cursor:pointer; cursor:hand;" src="http://3.bp.blogspot.com/_QYwcFosl4t0/SNHG1zhAcCI/AAAAAAAAAIc/GEG6J6vShx8/s400/sp07-hw3-p6.gif" border="0" alt=""id="BLOGGER_PHOTO_ID_5247193668527353890" /&gt;&lt;/a&gt;&lt;br /&gt;Determine the change in enthalpy in Joules for 20.0 g of heptane (C7H16) as it changes from a saturated liquid at 300 K [State 1] to a temperature of 370 K and a pressure of 58.7 kPa [State 4]; you can follow the hypothetical process path in the diagram to the right.  Do not use tables of thermodynamic properties, except to check your answers. (In other words, you will not get credit for the problem if you use the tables.)&lt;br /&gt;&lt;br /&gt;First, draw the states on a P-V or T-V diagram (4 pts).  Then, calculate the DH for each step in the path using what you know about the enthalpy for each step.  You might want to use the Antoine Equation to estimate the heat of vaporization of heptane at 300 K.  Use the average heat capacity of heptane gas over the temperature range of interest (is this assumption valid?).    &lt;br /&gt;&lt;br /&gt;Assume heptane gas is an ideal gas at the relevant temperatures and pressures.   &lt;br /&gt;&lt;br /&gt;For the analysis section, be sure to discuss how this result differs than what you would have done using just the thermodynamics data tables, as well as the validity of your assumptions (5 pts).&lt;br /&gt;&lt;br /&gt;HINTS: The key to the first step in this HPP is the Clausius-Clapeyron Equation. Use the Antoine equation to help you estimate the latent heat of vaporization at T1. In the second step, interpolate on the Cp data from the NIST WebBook to determine Cp(T1) and Cp(T2). Then, use the average of these two Cp's to evaluate the change in enthalpy. All you need to do is think a little bit and you will see how to evaluate ΔU34.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=2666081610880584242"&gt;6 Old Comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-4312554622285303202?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #3, P6 - Hypothetical Process Paths and the Latent Heat of Vaporization - 24 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/4312554622285303202/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=4312554622285303202' title='7 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4312554622285303202'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4312554622285303202'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-3-p6-hypothetical-process.html' title='TE 303 - HW #3, P6 - Hypothetical Process Paths and the Latent Heat of Vaporization - 24 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_QYwcFosl4t0/SNHG1zhAcCI/AAAAAAAAAIc/GEG6J6vShx8/s72-c/sp07-hw3-p6.gif' height='72' width='72'/><thr:total>7</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-5052550425875053027</id><published>2008-09-10T20:48:00.000-07:00</published><updated>2008-09-10T20:59:20.631-07:00</updated><title type='text'>TE 303 - HW #2, P1 - Steam Table Fundamentals - 8 pts</title><content type='html'>Complete the following table for water.  Be sure to cite which source of thermodynamic data tables that you used.       &lt;br /&gt;       &lt;br /&gt;T(oC)    P(kPa)    H(kJ/kg)    x(kg vap/kg)    Phase Description&lt;br /&gt;&lt;br /&gt;a.) P = 200 kPa and x = 0.7 kg vap/kg  &lt;br /&gt;b.) T = 140 degC and H = 1800 kJ/kg&lt;br /&gt;c.) P = 950 kPa and x = 0 kg vap/kg    &lt;br /&gt;d.) T = 80 degC and P = 500 kPa      &lt;br /&gt;e.) P = 800 kPa and H = 3161.7 kJ/kg&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=5467886024954868056"&gt;OLD comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-5052550425875053027?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #2, P1 - Steam Table Fundamentals - 8 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/5052550425875053027/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=5052550425875053027' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5052550425875053027'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5052550425875053027'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-2-p1-steam-table-fundamentals.html' title='TE 303 - HW #2, P1 - Steam Table Fundamentals - 8 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-2692461001820548877</id><published>2008-09-10T20:45:00.000-07:00</published><updated>2008-09-10T21:00:12.312-07:00</updated><title type='text'>TE 303 - HW #2, P2 - R-134a Table Fundamentals - 8 pts</title><content type='html'>Complete the following table for R-134a.  Be sure to cite which source of thermodynamic data tables that you used.       &lt;br /&gt;       &lt;br /&gt;T(oF)    P(psia)    U(Btu/lbm)    x(lbm vap/lbm)    Phase Description&lt;br /&gt;&lt;br /&gt;a.) P = 80 psia and U = 126      Btu/lbm&lt;br /&gt;b.) T = 15 degF and x = 0.6 lbm vap/lbm &lt;br /&gt;c.) T = 10 degF and P = 70 psia      &lt;br /&gt;d.) P = 180 psia and U = 226 Btu/lbm&lt;br /&gt;e.) T = 110 degF and x = 1.0 lbm vap/lbm&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=7662934611492284761"&gt;OLD comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-2692461001820548877?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #2, P2 - R-134a Table Fundamentals - 8 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/2692461001820548877/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=2692461001820548877' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2692461001820548877'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2692461001820548877'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-2-p2-r-134a-table.html' title='TE 303 - HW #2, P2 - R-134a Table Fundamentals - 8 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-5197285516184325419</id><published>2008-09-10T20:43:00.000-07:00</published><updated>2008-09-10T21:00:53.889-07:00</updated><title type='text'>TE 303 - HW #2, P3 - R-134a Table Fundamentals - 9 pts</title><content type='html'>A 0.5 m3 vessel contains 10 kg of R-134a at -20oC.  Determine…&lt;br /&gt;   &lt;br /&gt;a.) The pressure in kPa    &lt;br /&gt;b.) The total internal energy in kJ    &lt;br /&gt;c.) The volume occupied by the liquid phase in m3&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=7628005115350426267"&gt;OLD comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-5197285516184325419?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #2, P3 - R-134a Table Fundamentals - 9 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/5197285516184325419/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=5197285516184325419' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5197285516184325419'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5197285516184325419'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-2-p3-r-134a-table.html' title='TE 303 - HW #2, P3 - R-134a Table Fundamentals - 9 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-2109674862761717488</id><published>2008-09-10T20:42:00.000-07:00</published><updated>2008-09-10T21:02:06.008-07:00</updated><title type='text'>TE 303 - HW #2, P4 - Isochoric Heating of Water - 8 pts</title><content type='html'>Five kilograms of H2O are contained in a closed, rigid tank at an initial pressure of 20 bar and a quality of 50%.  Heat transfer occurs until the tank contains only saturated vapor.  Determine the volume of the tank, in m3, and the final pressure in bar.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=7628005115350426267"&gt;OLD comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-2109674862761717488?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #2, P4 - Isochoric Heating of Water - 8 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/2109674862761717488/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=2109674862761717488' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2109674862761717488'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2109674862761717488'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-2-p4-isochoric-heating-of.html' title='TE 303 - HW #2, P4 - Isochoric Heating of Water - 8 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-7285478913465911489</id><published>2008-09-10T20:41:00.000-07:00</published><updated>2008-09-10T21:02:56.962-07:00</updated><title type='text'>TE 303 - HW #2, P5 - Isobaric Expansion of Water - 12 pts</title><content type='html'>A piston-and-cylinder device initially contains 50 L of liquid water at 25oC and 300 kPa.  Heat is added to the water at constant pressure until the entire liquid is vaporized.&lt;br /&gt;      &lt;br /&gt;a.) What is the mass of the water in the cylinder in kg ?      &lt;br /&gt;b.) What is the final temperature of the water in the cylinder in oC ?      &lt;br /&gt;c.) Determine the total enthalpy change of the water for this process, in kJ.      &lt;br /&gt;d.) Show the process on a completely labeled TV Diagram.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=7857585285568595663"&gt;OLD comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-7285478913465911489?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #2, P5 - Isobaric Expansion of Water - 12 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/7285478913465911489/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=7285478913465911489' title='3 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7285478913465911489'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7285478913465911489'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-2-p5-isobaric-expansion-of.html' title='TE 303 - HW #2, P5 - Isobaric Expansion of Water - 12 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>3</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-8545855738560873110</id><published>2008-09-10T20:40:00.001-07:00</published><updated>2008-09-10T21:03:42.760-07:00</updated><title type='text'>TE 303 - HW #2, P6 - Inflating an Automobile Tire - 12 pts</title><content type='html'>The air in an automobile tire with a volume of 0.53 ft3 is at 90oF and 20 psig.  Determine the mass of air that must be added to raise the pressure to the recommended value of 30 psig.  Assume atmospheric pressure is 14.7 psia and both the temperature and the volume of the air in the tire remain constant as it is inflated.  Assume that the air in the tire behaves as an ideal gas, but then check the validity of this assumption.&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=8717452933460962970"&gt;OLD comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-8545855738560873110?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #2, P6 - Inflating an Automobile Tire - 12 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/8545855738560873110/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=8545855738560873110' title='5 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8545855738560873110'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8545855738560873110'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-2-p6-inflating-automobile.html' title='TE 303 - HW #2, P6 - Inflating an Automobile Tire - 12 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>5</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-5754618797172689314</id><published>2008-09-10T20:38:00.000-07:00</published><updated>2008-09-10T21:04:25.638-07:00</updated><title type='text'>TE 303 - HW #2, P7 - An Application of Equations of State - 25 pts</title><content type='html'>A 0.016773 m3 tank contains 1 kg of R-134a at 110oC. Determine the pressure of the refrigerant using:       &lt;br /&gt;       &lt;br /&gt;a.) The Ideal Gas EOS      &lt;br /&gt;b.) The Compressibility Factor EOS      &lt;br /&gt;c.) The R-134a Tables      &lt;br /&gt;d.) The van der Waal EOS      &lt;br /&gt;e.) The Soave-Redlich-Kwong EOS      &lt;br /&gt;       &lt;br /&gt;In your analysis, be sure to discuss a comparison of these equations of states (5 points).&lt;br /&gt;&lt;br /&gt;&lt;a href="https://www.blogger.com/comment.g?blogID=20953269&amp;postID=4599941438526385121"&gt;OLD comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-5754618797172689314?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #2, P7 - An Application of Equations of State - 25 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/5754618797172689314/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=5754618797172689314' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5754618797172689314'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5754618797172689314'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-2-p7-application-of-equations.html' title='TE 303 - HW #2, P7 - An Application of Equations of State - 25 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-3654566154637955482</id><published>2008-09-10T20:37:00.000-07:00</published><updated>2008-09-10T21:05:23.049-07:00</updated><title type='text'>TE 303 - HW #2, P8 - Relative Humidity and Fogged Glasses - 8 pts</title><content type='html'>The Campus Police heard that you were a thermodynamics guru, so they have come to you to help figure out if a witness to a crime is credible.  The eyewitness claims that upon entering her apartment complex, she saw the suspect leaving the downstairs apartment with some electronics equipment.  Since the eyewitness must wear glasses and stated that she was wearing them at the time, the Campus Police want to know if her glasses would have fogged up when entering the building and thus obstructed her view.  The temperature of the apartment complex was measured to be 20 °C, and the outdoor temperature to be 10oC.  A humidity gauge indicated that the relative humidity in the apartment complex is 55%.  Assuming that the eyewitness did not have anti-fog lenses, do you think that this eyewitness could have been obstructed by fogged lenses?  Provide supporting calculations.&lt;br /&gt;&lt;br /&gt;&lt;a href="http://www.blogger.com/post-edit.g?blogID=20953269&amp;postID=6435750027803257024"&gt;OLD comments&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-3654566154637955482?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #2, P8 - Relative Humidity and Fogged Glasses - 8 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/3654566154637955482/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=3654566154637955482' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3654566154637955482'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3654566154637955482'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/09/te-303-hw-2-p1-relative-humidity-and.html' title='TE 303 - HW #2, P8 - Relative Humidity and Fogged Glasses - 8 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-380909403480403588</id><published>2008-08-21T18:11:00.000-07:00</published><updated>2008-08-21T18:27:53.276-07:00</updated><title type='text'>TE 303 - Welcome to the LearnThermo Blog</title><content type='html'>For each homework problem that Dr. Pasquinelli assigns, I will post the problem statement on this blog.  If you have any questions about the problem, click on the small red "comments" at the end of the problem statement.  This will take you to a page where you can see all of the questions that you classmates asked, as well as my answers.  If nothing you find on this page answers your question, then you can type in a new question for me.  You should probably choose the "Name/URL" option for your identity.  This will let you make up any name you like.  This helps me state which question I am answering.  But you don't need to use your real name.  That way you and I can interact and no one will know who you are.&lt;br /&gt;&lt;br /&gt;I will check this blog twice per day during the week, but you cannot rely on me on the weekend.  I will probably only check the blog on Sunday night.&lt;br /&gt;&lt;br /&gt;BUT I encourage you to answer each others questions !  You don't really, really (Shrek) understand something until you can explain it to someone else.  So, try to help someone.  It is anonymous.  You might get a deeper understanding of the problem, and helping someone learn is a good thing to do.&lt;br /&gt;&lt;br /&gt;I have blogged (with my students) many of the problems Dr. Pasquinelli will use in this course.  You can search this blog to see the questions and answers that are already posted.  I suggest you focus your search on March through June 2007.&lt;br /&gt;&lt;br /&gt;You might also consider the supplemental example problems for Thermo-CD.  These are posted on my LearnThermo webiste.  Here is the link that goes directly to the additional example problems:&lt;br /&gt;&lt;a href="http://www.learnthermo.com/subjects/intro-thermo/examples.php"&gt;LearnThermo.com Examples&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;I look forward to working with you.&lt;br /&gt;&lt;br /&gt;Adios,&lt;br /&gt;Dr. B&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-380909403480403588?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://www.learnthermo.com/subjects/intro-thermo/examples.php' title='TE 303 - Welcome to the LearnThermo Blog'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/380909403480403588/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=380909403480403588' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/380909403480403588'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/380909403480403588'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/08/te-303-welcome-to-ilearnthermo-blog.html' title='TE 303 - Welcome to the LearnThermo Blog'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-3464423836487070332</id><published>2008-08-21T18:10:00.000-07:00</published><updated>2008-08-21T18:11:12.620-07:00</updated><title type='text'>TE 303 - HW #1, P1 - Mass, Force, Density and Acceleration - 10 pts</title><content type='html'>A closed system consists of 0.5 lbmole of liquid water and occupies a volume of 0.145 ft3.  Determine the weight of the system, in lbf, and the average density, in lbm/ft3, at a location where the acceleration of gravity is g = 30.5 ft/s2.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-3464423836487070332?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #1, P1 - Mass, Force, Density and Acceleration - 10 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/3464423836487070332/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=3464423836487070332' title='2 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3464423836487070332'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/3464423836487070332'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/08/te-303-hw-1-p1-mass-force-density-and.html' title='TE 303 - HW #1, P1 - Mass, Force, Density and Acceleration - 10 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-1172271091721864013</id><published>2008-08-21T18:09:00.000-07:00</published><updated>2008-08-21T18:10:10.116-07:00</updated><title type='text'>TE 303 - HW #1, P2 - Mass, Weight and Acceleration - 6 pts</title><content type='html'>The weight of an object on an orbiting space station is measured to be 42 N based on an artificial  acceleration of 6 m/s2.  What is the weight o f the object, in N, on Earth, where g = 9.81 m/s2 ?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-1172271091721864013?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #1, P2 - Mass, Weight and Acceleration - 6 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/1172271091721864013/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=1172271091721864013' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1172271091721864013'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1172271091721864013'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/08/te-303-hw-1-p2-mass-weight-and.html' title='TE 303 - HW #1, P2 - Mass, Weight and Acceleration - 6 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-2171021462930479568</id><published>2008-08-21T18:08:00.000-07:00</published><updated>2008-08-21T18:09:04.170-07:00</updated><title type='text'>TE 303 - HW #1, P3 - NOx Emissions: UNITS  - 6 pts</title><content type='html'>A typical car driven 12,000 miles/year emits to the atmosphere about 11 kg/year of NOx (nitrogen oxides), which causes smog in cities.  Natural gas burned in a home furnace emits about 4.3 g of NOx per therm and electric power plants emit about 7.1 g NOx per kWh of electricity produced.  Consider a household that has two cars and consumes 9,000 kWh of electricity and 1,200 therms of natural gas.  Determine the amount of NOx emission to the atmosphere per year for which the household is responsible.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-2171021462930479568?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #1, P3 - NOx Emissions: UNITS  - 6 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/2171021462930479568/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=2171021462930479568' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2171021462930479568'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2171021462930479568'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/08/te-303-hw-1-p3-nox-emissions-units-6.html' title='TE 303 - HW #1, P3 - NOx Emissions: UNITS  - 6 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-6630324804747623660</id><published>2008-08-21T18:04:00.000-07:00</published><updated>2008-08-21T18:08:04.386-07:00</updated><title type='text'>TE 303 - HW #1, P4 - Temperature Conversions: Celsius to Fahrenheit  - 12 pts</title><content type='html'>Convert the following temperatures from oC to oF.&lt;br /&gt;a.) 21 oC&lt;br /&gt;b.) -17.78 oC&lt;br /&gt;c.) -50 oC&lt;br /&gt;d.) 300 oC&lt;br /&gt;e.) 100 oC&lt;br /&gt;f.) -273.15 oC&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-6630324804747623660?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #1, P4 - Temperature Conversions: Celsius to Fahrenheit  - 12 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/6630324804747623660/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=6630324804747623660' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/6630324804747623660'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/6630324804747623660'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/08/te-303-hw-1-p4-temperature-conversions.html' title='TE 303 - HW #1, P4 - Temperature Conversions: Celsius to Fahrenheit  - 12 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-8442121783948909913</id><published>2008-08-21T18:02:00.000-07:00</published><updated>2008-08-21T18:07:26.837-07:00</updated><title type='text'>TE 303 - HW #1, P5 - Temperature Conversions: Fahrenheit to Celsius - 12 pts</title><content type='html'>Convert the following temperatures from oF to oC.&lt;br /&gt;&lt;br /&gt;a.) 212 oF&lt;br /&gt;b.) 68 oF&lt;br /&gt;c.) 32 oF&lt;br /&gt;d.) 0 oF&lt;br /&gt;e.) -40 oF&lt;br /&gt;f.) -459.67 oF&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-8442121783948909913?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #1, P5 - Temperature Conversions: Fahrenheit to Celsius - 12 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/8442121783948909913/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=8442121783948909913' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8442121783948909913'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8442121783948909913'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/08/te-303-hw-1-p5-temperature-conversions.html' title='TE 303 - HW #1, P5 - Temperature Conversions: Fahrenheit to Celsius - 12 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-4386676384032936926</id><published>2008-08-21T18:01:00.000-07:00</published><updated>2008-08-21T18:02:07.627-07:00</updated><title type='text'>TE 303 - HW #1, P6 - Temperature Change - 6 pts</title><content type='html'>The temperature of a system rises by 72oC during a heating process.  Express this temperature increase in Kelvins and degrees Rankine.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-4386676384032936926?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #1, P6 - Temperature Change - 6 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/4386676384032936926/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=4386676384032936926' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4386676384032936926'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4386676384032936926'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/08/te-303-hw-1-p6-temperature-change-6-pts.html' title='TE 303 - HW #1, P6 - Temperature Change - 6 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-4930414157335020767</id><published>2008-08-21T17:57:00.000-07:00</published><updated>2008-08-21T18:00:48.411-07:00</updated><title type='text'>TE 303 - HW #1, P7 - Absolute and gauge Pressures - 15 pts</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_QYwcFosl4t0/SK4Pq8fNUoI/AAAAAAAAAH4/IVBNSfFX02o/s1600-h/sp07-hw1-p7-small.gif"&gt;&lt;img style="float:left; margin:0 10px 10px 0;cursor:pointer; cursor:hand;" src="http://1.bp.blogspot.com/_QYwcFosl4t0/SK4Pq8fNUoI/AAAAAAAAAH4/IVBNSfFX02o/s400/sp07-hw1-p7-small.gif" border="0" alt=""id="BLOGGER_PHOTO_ID_5237140647144411778" /&gt;&lt;/a&gt;&lt;br /&gt;Tank A lies inside of Tank B, as shown in the figure.  Pressure gauge A is located inside Tank B and reads 1.4 bar.   Both tanks contain air.  The manometer connected to Tank B contains mercury (r = 13.59 g/cm3).  The manometer reading is  h = 20 cm, atmospheric pressure is 101 kPa and g = 9.81 m/s2.  Determine the absolute pressures inside Tank A and Tank B in kPa.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-4930414157335020767?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=4575' title='TE 303 - HW #1, P7 - Absolute and gauge Pressures - 15 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/4930414157335020767/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=4930414157335020767' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4930414157335020767'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4930414157335020767'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/08/te-303-hw-1-p7-absolute-and-gauge.html' title='TE 303 - HW #1, P7 - Absolute and gauge Pressures - 15 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://1.bp.blogspot.com/_QYwcFosl4t0/SK4Pq8fNUoI/AAAAAAAAAH4/IVBNSfFX02o/s72-c/sp07-hw1-p7-small.gif' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-5339479172468184320</id><published>2008-08-21T17:45:00.000-07:00</published><updated>2008-08-21T17:58:17.865-07:00</updated><title type='text'>TE 303 - HW#1, P8 - Differential, Multi-Fluid Manometer - 18 pts</title><content type='html'>&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_QYwcFosl4t0/SK4M4DXtqsI/AAAAAAAAAHw/A59dVwnFgXM/s1600-h/sp07-hw1-p8.gif"&gt;&lt;img style="float:left; margin:0 10px 10px 0;cursor:pointer; cursor:hand;" src="http://2.bp.blogspot.com/_QYwcFosl4t0/SK4M4DXtqsI/AAAAAAAAAHw/A59dVwnFgXM/s400/sp07-hw1-p8.gif" border="0" alt=""id="BLOGGER_PHOTO_ID_5237137573795441346" /&gt;&lt;/a&gt;&lt;br /&gt;Fresh water and seawater flowing in parallel, horizontal pipelines are connected to each other by a double u-tube manometer, as shown in the figure.  Determine the pressure difference between the two pipelines in kPa.  Assume the density of seawater to be 1035 kg/m3.  Can the air column be ignored in this analysis ?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-5339479172468184320?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://moodlepilot.ncsu.edu/course/view.php?id=457' title='TE 303 - HW#1, P8 - Differential, Multi-Fluid Manometer - 18 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/5339479172468184320/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=5339479172468184320' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5339479172468184320'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/5339479172468184320'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2008/08/hw1-p8-differential-multi-fluid.html' title='TE 303 - HW#1, P8 - Differential, Multi-Fluid Manometer - 18 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://2.bp.blogspot.com/_QYwcFosl4t0/SK4M4DXtqsI/AAAAAAAAAHw/A59dVwnFgXM/s72-c/sp07-hw1-p8.gif' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-7369146475165065595</id><published>2007-06-01T17:20:00.000-07:00</published><updated>2007-06-01T17:26:04.392-07:00</updated><title type='text'>Final Exam 2007</title><content type='html'>Please post any questions you have here.  I will be responsive on Sunday, but not much on Saturday.&lt;br /&gt;&lt;br /&gt;It has been a pleasure working with all of you.  I hope you do well on the final.  Remember you can use 3 8.5" x 11" cheat sheets (with writing on both sides) during the final.&lt;br /&gt;&lt;br /&gt;We will take the class photo before the final on Monday morning.  Sorry I forgot about it today.  It is optional, you can choose not to be in the photo if you wish.&lt;br /&gt;&lt;br /&gt;Best of luck in your career and in life.&lt;br /&gt;&lt;br /&gt;Adios,&lt;br /&gt;Dr. B&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-7369146475165065595?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://anytime.engr.washington.edu/course/view.php?id=125' title='Final Exam 2007'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/7369146475165065595/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=7369146475165065595' title='48 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7369146475165065595'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7369146475165065595'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2007/06/final-exam-2007.html' title='Final Exam 2007'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>48</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-2790488751019442128</id><published>2007-05-22T18:46:00.002-07:00</published><updated>2007-05-22T18:47:29.611-07:00</updated><title type='text'>HW #9, P1 - Brayton Cycle with Variable Heat Capacities - 6 pts</title><content type='html'>A gas turbine power plant operates on the basic Brayton Cycle.  Air is the working fluid and the cycle delivers 15 MW of power.  The minimum and maximum temperatures in the cycle are 310 K and 900 K, respectively.  The air pressure at the compressor outlet is 8 times the pressure at the compressor inlet.  Assuming an isentropic efficiency of 80% for the compressor and 86% for the turbine, determine the mass flow rate of air through the cycle.  Assume that air behaves as an ideal gas, but do not assume that the heat capacities of the air are constants.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-2790488751019442128?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://anytime.engr.washington.edu/course/view.php?id=125' title='HW #9, P1 - Brayton Cycle with Variable Heat Capacities - 6 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/2790488751019442128/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=2790488751019442128' title='6 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2790488751019442128'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2790488751019442128'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2007/05/hw-9-p1-brayton-cycle-with-variable.html' title='HW #9, P1 - Brayton Cycle with Variable Heat Capacities - 6 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>6</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-4506467416387151810</id><published>2007-05-22T18:46:00.001-07:00</published><updated>2007-05-22T18:46:53.703-07:00</updated><title type='text'>HW #9, P2 - Brayton Cycle with Regeneration - 8 pts</title><content type='html'>A Brayton Cycle with Regeneration using air as the working fluid has a pressure ratio of 7.  The minimum and maximum temperatures in the cycle are 310 K and 1150 K.  Assuming an isentropic efficiency of 75% for the compressor and 82% for the turbine and an efffectiveness of 65% for the regenerator, determine...&lt;br /&gt;&lt;br /&gt;a.) The temperature of the turbine effluent.&lt;br /&gt;b.) The net work output, in kJ/kg of air flowing through the system.&lt;br /&gt;c.) The thermal efficiency of the cycle.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-4506467416387151810?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://anytime.engr.washington.edu/course/view.php?id=125' title='HW #9, P2 - Brayton Cycle with Regeneration - 8 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/4506467416387151810/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=4506467416387151810' title='8 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4506467416387151810'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/4506467416387151810'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2007/05/hw-9-p2-brayton-cycle-with-regeneration.html' title='HW #9, P2 - Brayton Cycle with Regeneration - 8 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>8</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-8938953327829447271</id><published>2007-05-22T18:45:00.000-07:00</published><updated>2007-05-22T18:46:00.782-07:00</updated><title type='text'>HW #9, P3 - Effect of Turbine Feed T on Rankine Cycle Efficiency  - 6 pts</title><content type='html'>Steam enters the turbine of a basic Rankine power cycle at a pressure of 10 MPa and a temperature T2, and expands adiabatically to 6 kPa.  The isentropic turbine efficiency is 85%.  Saturated liquid water leaves the condenser at 6 kPa and the isentropic pump efficiency is 82%.&lt;br /&gt;&lt;br /&gt;a.) For T2 = 580oC, determine the quality of the turbine effluent and the thermal efficiency of the cycle.&lt;br /&gt;&lt;br /&gt;b.) Plot the quality of the turbine effluent and the thermal efficiency of the cycle for values of T2 ranging from 580oC to 700oC at 10oC increments.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-8938953327829447271?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://anytime.engr.washington.edu/course/view.php?id=125' title='HW #9, P3 - Effect of Turbine Feed T on Rankine Cycle Efficiency  - 6 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/8938953327829447271/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=8938953327829447271' title='11 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8938953327829447271'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8938953327829447271'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2007/05/hw-9-p3-effect-of-turbine-feed-t-on.html' title='HW #9, P3 - Effect of Turbine Feed T on Rankine Cycle Efficiency  - 6 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>11</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-8161960493840660158</id><published>2007-05-22T18:42:00.000-07:00</published><updated>2007-05-22T18:44:58.986-07:00</updated><title type='text'>HW #9, P4 - Special Rankine Cycle with Reheat and Regeneration - 8 pts</title><content type='html'>A power plant operates on a regenerative vapor power cycle with one closed feedwater heater.  Steam enters the high-pressure turbine at 120 bar and 520oC and expands to 10 bar, where some of the steam is extracted and diverted to a closed feedwater heater.  Condensate leaves the feedwater heater as a saturated liquid at 10 bar and then passes through an expansion valve before it is combined with the effluent from the low-pressure turbine.  This combined stream flows to the condenser.  The boiler feed leaves the feedwater heater at 120 bar and 170oC.  The condenser pressure is 0.06 bar.  Each turbine stage has an isentropic efficiency of 82%.  The pump is essentially isentropic.&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_QYwcFosl4t0/RlOcdSMdjMI/AAAAAAAAAFU/7ch2hacCeDs/s1600-h/Rank-Regen-closed-FWH-flow.png"&gt;&lt;img style="display:block; margin:0px auto 10px; text-align:center;cursor:pointer; cursor:hand;" src="http://4.bp.blogspot.com/_QYwcFosl4t0/RlOcdSMdjMI/AAAAAAAAAFU/7ch2hacCeDs/s320/Rank-Regen-closed-FWH-flow.png" border="0" alt=""id="BLOGGER_PHOTO_ID_5067566032636185794" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;Determine...&lt;br /&gt;a.) The thermal efficiency of the cycle.      &lt;br /&gt;b.) The mass flow rate of water/steam through the boiler in kg/h. if the net power output of the cycle is 320 MW.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-8161960493840660158?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://anytime.engr.washington.edu/course/view.php?id=125' title='HW #9, P4 - Special Rankine Cycle with Reheat and Regeneration - 8 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/8161960493840660158/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=8161960493840660158' title='7 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8161960493840660158'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8161960493840660158'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2007/05/hw-9-p4-special-rankine-cycle-with.html' title='HW #9, P4 - Special Rankine Cycle with Reheat and Regeneration - 8 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://4.bp.blogspot.com/_QYwcFosl4t0/RlOcdSMdjMI/AAAAAAAAAFU/7ch2hacCeDs/s72-c/Rank-Regen-closed-FWH-flow.png' height='72' width='72'/><thr:total>7</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-1719880059701460050</id><published>2007-05-22T18:41:00.000-07:00</published><updated>2007-05-22T18:42:12.479-07:00</updated><title type='text'>HW #9, P5 - Helium Gas Refrigeration Cycle - 6 pts</title><content type='html'>A gas refrigeration cycle with a pressure ratio of 3 uses helium as the working fluid.  The temperature of the helium is -10oC at the compressor inlet and 50oC at the turbine inlet.  Assuming adiabatic efficiencies of 82% for both the turbine and the compressor, determine...&lt;br /&gt;&lt;br /&gt;a.) The minimum temperature in the cycle.&lt;br /&gt;b.) The coefficient of performance.&lt;br /&gt;c.) The mass flow rate of the helium in kg/s for a refrigeration load of 12 kW.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-1719880059701460050?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://anytime.engr.washington.edu/course/view.php?id=125' title='HW #9, P5 - Helium Gas Refrigeration Cycle - 6 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/1719880059701460050/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=1719880059701460050' title='8 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1719880059701460050'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1719880059701460050'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2007/05/hw-9-p5-helium-gas-refrigeration-cycle.html' title='HW #9, P5 - Helium Gas Refrigeration Cycle - 6 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>8</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-1544558472537949790</id><published>2007-05-22T18:35:00.000-07:00</published><updated>2007-05-22T18:41:00.089-07:00</updated><title type='text'>HW #9, P6 - Ammonia Cascade Refrigeration Cycle - 8 pts</title><content type='html'>The diagram shows a two-stage, vapor-compression refrigeration system that uses ammonia as the working fluid.  The system uses a flash drum to achieve intercooling.  The evaporator has a refrigeration capacity of 30 tons and produces a saturated vapor effluent  at -20oF.  In the first compressor stage, the refrigerant is compressed adiabatically to 80 psia, which is the pressure in the mixer.  Saturated vapor at 80 psia enters the second compressor stage and is compressed adiabatically to 250 psia.  Each compressor stage has an isentropic efficiency of 85%.  Ther are no significant pressure drops as the refrigerant passes through the heat exchangers.  Saturated liquid enters each expansion valve.&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_QYwcFosl4t0/RlObHiMdjLI/AAAAAAAAAFM/5Z17cUpyXKM/s1600-h/VCR-multistage-flow.png"&gt;&lt;img style="display:block; margin:0px auto 10px; text-align:center;cursor:pointer; cursor:hand;" src="http://1.bp.blogspot.com/_QYwcFosl4t0/RlObHiMdjLI/AAAAAAAAAFM/5Z17cUpyXKM/s320/VCR-multistage-flow.png" border="0" alt=""id="BLOGGER_PHOTO_ID_5067564559462403250" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;Determine...&lt;br /&gt;a.) The mass flow rate of R-134a through each compressor in lbm/h.&lt;br /&gt;b.) The power input to each compressor in Btu/h.&lt;br /&gt;c.) The coefficient of performance of the cycle.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-1544558472537949790?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://anytime.engr.washington.edu/course/view.php?id=125' title='HW #9, P6 - Ammonia Cascade Refrigeration Cycle - 8 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/1544558472537949790/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=1544558472537949790' title='6 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1544558472537949790'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1544558472537949790'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2007/05/hw-9-p1-problem-title-here-4-pts.html' title='HW #9, P6 - Ammonia Cascade Refrigeration Cycle - 8 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://1.bp.blogspot.com/_QYwcFosl4t0/RlObHiMdjLI/AAAAAAAAAFM/5Z17cUpyXKM/s72-c/VCR-multistage-flow.png' height='72' width='72'/><thr:total>6</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-2121072665142549332</id><published>2007-05-22T18:30:00.000-07:00</published><updated>2007-05-22T18:35:14.339-07:00</updated><title type='text'>HW #9, P7 - Vapor-Compression Heat Pump - 6 pts</title><content type='html'>A vapor-compression heat pump uses R-134a as the working fluid.  The refrigerant enters the compressor at 2.4 bar and 0oC at a volumetric flow rate of 0.60 m3/min.  Compression is adiabatic to 9 bar and 60oC and saturated liquid leaves the condenser at 9 bar.  Determine...&lt;br /&gt;&lt;br /&gt;a.) The power input to the compressor in kW.&lt;br /&gt;b.) The heating capacity of the heat pump in kW.&lt;br /&gt;c.) The coefficient of performance.&lt;br /&gt;d.) The isentropic compressor efficiency.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-2121072665142549332?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://anytime.engr.washington.edu/course/view.php?id=125' title='HW #9, P7 - Vapor-Compression Heat Pump - 6 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/2121072665142549332/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=2121072665142549332' title='3 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2121072665142549332'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/2121072665142549332'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2007/05/hw-9-p7-vapor-compression-heat-pump-6.html' title='HW #9, P7 - Vapor-Compression Heat Pump - 6 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>3</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-7834940620352291163</id><published>2007-05-21T17:31:00.000-07:00</published><updated>2007-05-21T17:33:05.584-07:00</updated><title type='text'>Test #2 - Ch 5 to 8, May 22, 2007</title><content type='html'>Please post here any questions you might have about Test #2.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-7834940620352291163?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://anytime.engr.washington.edu/course/view.php?id=125' title='Test #2 - Ch 5 to 8, May 22, 2007'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/7834940620352291163/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=7834940620352291163' title='4 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7834940620352291163'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7834940620352291163'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2007/05/test-2-ch-5-to-8-may-22-2007.html' title='Test #2 - Ch 5 to 8, May 22, 2007'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>4</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-8996074917269568071</id><published>2007-05-14T16:33:00.001-07:00</published><updated>2007-05-14T16:33:49.906-07:00</updated><title type='text'>HW #8, P1 - Back-Work Ratio of a Steam Power Cycle - 4 pts</title><content type='html'>Consider a steam power plant that operates between the pressure limits of 10 MPa and 20 kPa.  Steam enters the pump as a saturated liquid and leaves the turbine as a saturated vapor.  Determine the back work ratio (BWR is the ratio of the work delivered by the turbine to the work consumed by the pump).   Assume the entire cycle to be reversible and the heat losses from the pump and the turbine to be negligible.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-8996074917269568071?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://anytime.engr.washington.edu/course/view.php?id=125' title='HW #8, P1 - Back-Work Ratio of a Steam Power Cycle - 4 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/8996074917269568071/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=8996074917269568071' title='7 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8996074917269568071'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/8996074917269568071'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2007/05/hw-8-p1-back-work-ratio-of-steam-power.html' title='HW #8, P1 - Back-Work Ratio of a Steam Power Cycle - 4 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>7</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-1997269837228832385</id><published>2007-05-14T16:32:00.000-07:00</published><updated>2007-05-14T16:33:10.922-07:00</updated><title type='text'>HW #8, P2 - Isentropic Efficiency of a CO2 Compressor - 4 pts</title><content type='html'>Carbon dioxide enters an adiabatic compressor at 100 kPa and 300 K at a rate of 2.2 kg/s and exits at 600 kP and 450 K.  Neglecting changes in kinetic and potential energies, determine the isentropic efficiency of the compressor.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-1997269837228832385?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://anytime.engr.washington.edu/course/view.php?id=125' title='HW #8, P2 - Isentropic Efficiency of a CO2 Compressor - 4 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/1997269837228832385/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=1997269837228832385' title='2 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1997269837228832385'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1997269837228832385'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2007/05/hw-8-p2-isentropic-efficiency-of-co2.html' title='HW #8, P2 - Isentropic Efficiency of a CO2 Compressor - 4 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-7734588543568253758</id><published>2007-05-14T16:31:00.000-07:00</published><updated>2007-05-14T16:32:26.247-07:00</updated><title type='text'>HW #8, P3 - Analysis of an R-134a Compressor  - 5 pts</title><content type='html'>R-134a enters an adiabatic compressor as saturated vapor at 120 kPa at a rate of 0.30 m3/min and exits at 1.0 MPa.  If the isentropic efficiency of the compresor is 80%, determine…&lt;br /&gt;&lt;br /&gt;a.) The temperature of the R-134a at the outlet of the compressor.&lt;br /&gt;b.) The power input to the compressor in kW.&lt;br /&gt;c.) Show the process path on a TS Diagram that includes the two phase envelope and all relevant isobars.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-7734588543568253758?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://anytime.engr.washington.edu/course/view.php?id=125' title='HW #8, P3 - Analysis of an R-134a Compressor  - 5 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/7734588543568253758/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=7734588543568253758' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7734588543568253758'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7734588543568253758'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2007/05/hw-8-p3-analysis-of-r-134a-compressor-5.html' title='HW #8, P3 - Analysis of an R-134a Compressor  - 5 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-1772761372861707122</id><published>2007-05-14T16:29:00.000-07:00</published><updated>2007-05-15T16:31:13.041-07:00</updated><title type='text'>HW #8, P4 - Polytropic Compression of N2 with Varying delta - 6 pts</title><content type='html'>Nitrogen gas is compressed from 80 kPa and 27oC to 480 kPa by a 10 kW compressor.  Determine the mass flow rate of nitrogen through the compressor assuming the compression process is …&lt;br /&gt;&lt;br /&gt;a.) Isentropic, gamma = 1.4      &lt;br /&gt;b.) Polytropic with delta = 1.3      &lt;br /&gt;c.) Isothermal      &lt;br /&gt;d.) Ideal, two-stage polytropic with delta = 1.3&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-1772761372861707122?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://anytime.engr.washington.edu/course/view.php?id=125' title='HW #8, P4 - Polytropic Compression of N2 with Varying delta - 6 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/1772761372861707122/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=1772761372861707122' title='8 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1772761372861707122'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/1772761372861707122'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2007/05/hw-8-p4-polytropic-compression-of-n2.html' title='HW #8, P4 - Polytropic Compression of N2 with Varying delta - 6 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><thr:total>8</thr:total></entry><entry><id>tag:blogger.com,1999:blog-20953269.post-7124753858525493724</id><published>2007-05-14T16:28:00.000-07:00</published><updated>2007-05-14T21:52:37.781-07:00</updated><title type='text'>HW #8, P5 - Lost Work in a Heat Exchanger - 4 pts</title><content type='html'>A well-insulated shell-and-tube heat exchanger is used to heat water (CP = 4.18 kJ/kg-K) in the tubes from 20oC to 70oC at a rate of 4.5 kg/s.  Heat is supplied by hot oil (CP = 2.30 kJ/kg-K) that enters the shell side at 170oC at a rate of 10 kg/s.  Disregarding any heat loss from the heat exchanger, determine...&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_QYwcFosl4t0/Rkk8gAPTOKI/AAAAAAAAAFE/FgRwT5WU5Aw/s1600-h/SnT-HEX.png"&gt;&lt;img style="display:block; margin:0px auto 10px; text-align:center;cursor:pointer; cursor:hand;" src="http://3.bp.blogspot.com/_QYwcFosl4t0/Rkk8gAPTOKI/AAAAAAAAAFE/FgRwT5WU5Aw/s320/SnT-HEX.png" border="0" alt=""id="BLOGGER_PHOTO_ID_5064645776472488098" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;a.) The exit temperature of the oil.&lt;br /&gt;&lt;br /&gt;b.) The rate of entropy generation in the heat exchanger.&lt;br /&gt;&lt;br /&gt;c.) The rate at which work is lost due to the irreversible nature of heat transfer in this process in kW.  Assume the surroundings are at 20oC.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/20953269-7124753858525493724?l=learnthermo.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='related' href='http://anytime.engr.washington.edu/course/view.php?id=125' title='HW #8, P5 - Lost Work in a Heat Exchanger - 4 pts'/><link rel='replies' type='application/atom+xml' href='http://learnthermo.blogspot.com/feeds/7124753858525493724/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=20953269&amp;postID=7124753858525493724' title='3 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7124753858525493724'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/20953269/posts/default/7124753858525493724'/><link rel='alternate' type='text/html' href='http://learnthermo.blogspot.com/2007/05/hw-8-p5-lost-work-in-heat-exchanger-4.html' title='HW #8, P5 - Lost Work in a Heat Exchanger - 4 pts'/><author><name>Dr. B</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='23' height='32' src='http://1.bp.blogspot.com/_QYwcFosl4t0/SNHFFzSeocI/AAAAAAAAAIE/Pr1VcgCdp6U/S220/Baratuci_B_011.jpg'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/_QYwcFosl4t0/Rkk8gAPTOKI/AAAAAAAAAFE/FgRwT5WU5Aw/s72-c/SnT-HEX.png' height='72' width='72'/><thr:total>3</thr:total></entry></feed>
